1. Which one of the following four schemes (A-D) represents a step in the mechanism of the reaction in the box? Cl2, light (hv) CI + HCI H Cl-H A B H C D H OB OD oc O A

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**Question:**

1. Which one of the following four schemes (A-D) represents a step in the *mechanism* of the reaction in the box?

**Reaction in the Box:**

\[ \text{(Isobutane)} \rightarrow \text{(Chlorination)} \rightarrow \text{(Chloro isobutane) + HCl} \]  
**Reagents:** \(\text{Cl}_2, \text{light (hv)}\)

**Schemes:**

- **A:** Shows the abstraction of a hydrogen atom from isobutane by a chlorine radical (\(\text{Cl}^\cdot\)) to form isobutyl radical and HCl.
- **B:** Depicts a chlorine atom (\(\text{Cl}^\cdot\)) being added to a hydrogen, with an incorrect depiction of bond breaking and forming.
- **C:** Illustrates a chlorine molecule (\(\text{Cl}_2\)) approaching isobutane without cleavage, which is not typical in radical chlorination.
- **D:** Represents an abstraction of a hydrogen atom from isobutane by chlorine radical (\(\text{Cl}^\cdot\)), forming isobutyl radical and HCl.

**Multiple Choice Options:**

- ○ B
- ○ D
- ○ C
- ○ A

The correct answer represents the radical chain initiation and propagation step involving the abstraction of a hydrogen by a chlorine radical, which is typical for radical halogenation reactions.

**Graphs/Diagrams:**

- **Scheme A:** Displays an arrow from the hydrogen on isobutane to a chlorine radical, indicating the generation of isobutyl radical and HCl.
- **Scheme B:** Incorrectly shows a chlorine atom directly forming a new bond with hydrogen without any radical process.
- **Scheme C:** Shows two chlorine atoms approaching the isobutane, not representing radical formation.
- **Scheme D:** Similar to Scheme A with accurate radical abstraction depiction.
  
**Answer: Choice D**
Transcribed Image Text:**Question:** 1. Which one of the following four schemes (A-D) represents a step in the *mechanism* of the reaction in the box? **Reaction in the Box:** \[ \text{(Isobutane)} \rightarrow \text{(Chlorination)} \rightarrow \text{(Chloro isobutane) + HCl} \] **Reagents:** \(\text{Cl}_2, \text{light (hv)}\) **Schemes:** - **A:** Shows the abstraction of a hydrogen atom from isobutane by a chlorine radical (\(\text{Cl}^\cdot\)) to form isobutyl radical and HCl. - **B:** Depicts a chlorine atom (\(\text{Cl}^\cdot\)) being added to a hydrogen, with an incorrect depiction of bond breaking and forming. - **C:** Illustrates a chlorine molecule (\(\text{Cl}_2\)) approaching isobutane without cleavage, which is not typical in radical chlorination. - **D:** Represents an abstraction of a hydrogen atom from isobutane by chlorine radical (\(\text{Cl}^\cdot\)), forming isobutyl radical and HCl. **Multiple Choice Options:** - ○ B - ○ D - ○ C - ○ A The correct answer represents the radical chain initiation and propagation step involving the abstraction of a hydrogen by a chlorine radical, which is typical for radical halogenation reactions. **Graphs/Diagrams:** - **Scheme A:** Displays an arrow from the hydrogen on isobutane to a chlorine radical, indicating the generation of isobutyl radical and HCl. - **Scheme B:** Incorrectly shows a chlorine atom directly forming a new bond with hydrogen without any radical process. - **Scheme C:** Shows two chlorine atoms approaching the isobutane, not representing radical formation. - **Scheme D:** Similar to Scheme A with accurate radical abstraction depiction. **Answer: Choice D**
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