1. When choosing one skittle, are the events "selecting a red skittle" and "selecting a blue skittle" mutually exclusive? Yes 2. What is the probability that a red skittle is randomly chosen from the bag? PR÷ )= 7/31 3. What is the probability of choosing a blue skittle, putting it back, and then choosing a green skittle? P( B and G 75/3844 4. What is the probability of choosing a skittle that is not blue? P( B' ÷ )= 47/62 5. What is the probability of randomly choosing a green or blue skittle? PB or G ♦
1. When choosing one skittle, are the events "selecting a red skittle" and "selecting a blue skittle" mutually exclusive? Yes 2. What is the probability that a red skittle is randomly chosen from the bag? PR÷ )= 7/31 3. What is the probability of choosing a blue skittle, putting it back, and then choosing a green skittle? P( B and G 75/3844 4. What is the probability of choosing a skittle that is not blue? P( B' ÷ )= 47/62 5. What is the probability of randomly choosing a green or blue skittle? PB or G ♦
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![**Determining Probabilities**
**Instructions:** Given that a bag of skittles has 15 blue candies, 16 orange candies, 12 yellow, 14 red, and 5 green candies, find the probabilities for the following questions. Do not use any spaces in your answers.
1. **When choosing one skittle, are the events "selecting a red skittle" and "selecting a blue skittle" mutually exclusive?**
- **Yes**
2. **What is the probability that a red skittle is randomly chosen from the bag?**
- \( P(R) = \frac{7}{31} \)
3. **What is the probability of choosing a blue skittle, putting it back, and then choosing a green skittle?**
- \( P(B \text{ and } G) = \frac{75}{3844} \)
4. **What is the probability of choosing a skittle that is not blue?**
- \( P(B') = \frac{47}{62} \)
5. **What is the probability of randomly choosing a green or blue skittle?**
- \( P(G \text{ or } B) = \frac{10}{31} \)
6. **What is the probability of choosing a green skittle, eating it, and then choosing a yellow skittle?**
- \( P(G \text{ and } Y) = \frac{30}{1891} \)
7. **What is the probability of choosing a red skittle on the second try given that the first skittle was red and it was eaten?**
- \( P(R|R) = \)
Note: The data suggests that the bag contains different quantities of colored skittles. The total number of skittles can be calculated as:
\[ 15 (blue) + 16 (orange) + 12 (yellow) + 14 (red) + 5 (green) = 62 \]
It's crucial to use these total counts when calculating individual and compound probabilities. Ensure that the fractions are fully simplified in your answers where possible.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6178b39-0704-4d71-b440-614ab90e41c7%2F2e86a9ac-6658-44e0-a7c8-b1a77b083264%2Fahr79er_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Determining Probabilities**
**Instructions:** Given that a bag of skittles has 15 blue candies, 16 orange candies, 12 yellow, 14 red, and 5 green candies, find the probabilities for the following questions. Do not use any spaces in your answers.
1. **When choosing one skittle, are the events "selecting a red skittle" and "selecting a blue skittle" mutually exclusive?**
- **Yes**
2. **What is the probability that a red skittle is randomly chosen from the bag?**
- \( P(R) = \frac{7}{31} \)
3. **What is the probability of choosing a blue skittle, putting it back, and then choosing a green skittle?**
- \( P(B \text{ and } G) = \frac{75}{3844} \)
4. **What is the probability of choosing a skittle that is not blue?**
- \( P(B') = \frac{47}{62} \)
5. **What is the probability of randomly choosing a green or blue skittle?**
- \( P(G \text{ or } B) = \frac{10}{31} \)
6. **What is the probability of choosing a green skittle, eating it, and then choosing a yellow skittle?**
- \( P(G \text{ and } Y) = \frac{30}{1891} \)
7. **What is the probability of choosing a red skittle on the second try given that the first skittle was red and it was eaten?**
- \( P(R|R) = \)
Note: The data suggests that the bag contains different quantities of colored skittles. The total number of skittles can be calculated as:
\[ 15 (blue) + 16 (orange) + 12 (yellow) + 14 (red) + 5 (green) = 62 \]
It's crucial to use these total counts when calculating individual and compound probabilities. Ensure that the fractions are fully simplified in your answers where possible.
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