1. When an air capacitor with a capacitance of 400 nF (1 nF = 10-9) is connected to a power supply. the energy stored in the capacitor is 3x10-5J. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.42×10-5J. a) What is the potential difference between the capacitor plates before the insertion of the dielectric? b) What is the potential difference between the capacitor plates after the insertion of the dielectric? c) d) What is the dielectric constant of the slab? If the capacitor is disconnected from the r

1. When an air capacitor with a capacitance of 400 nF (1 nF = 10-9) is connected to a power supply. the energy stored in the capacitor is 3x10-5J. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.42×10-5J. a) What is the potential difference between the capacitor plates before the insertion of the dielectric? b) What is the potential difference between the capacitor plates after the insertion of the dielectric? c) d) What is the dielectric constant of the slab? If the capacitor is disconnected from the r

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

1. When an air capacitor with a capacitance of 400 nF (1 nF = 10-9) is connected to a power supply,
the energy stored in the capacitor is 3x10-5J. While the capacitor is kept connected to the power
supply, a slab of dielectric is inserted that completely fills the space between the plates. This
increases the stored energy by 2.42×10-5J.
a) What is the potential difference between the capacitor plates before the insertion of the
dielectric?
b) What is the potential difference between the capacitor plates after the insertion of the
dielectric?
c)
d)
What is the dielectric constant of the slab?
If the capacitor is disconnected from the power supply after the charging (the circuit is open),
then you insert the dielectric, what is the potential difference between the capacitor plates
after the insertion of the dielectric?
e) If the capacitor is disconnected from the power supply after the charging (the circuit is open),
then you insert the dielectric, what is the stored energy difference between the capacitor
plates after the insertion of the dielectric?

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