1. ) What weight of 98.5% KHC,HO, is equivalent to (a) 35 ml of 0.01 N NaOH,
2.) A 50.00-ml sample of calcium hydroxide solution required 19.50 ml of 0.1050 N hydrochloric acid in a titration. Calculate (a) the amount of Ca(OH), in the 50.00-ml sample and (b) the Ca(OH) a concentration in % w/v.
3.) If 25.00 ml of a hydrochloric acid solution were required in titration of a 0.6500-g sample of pure sodium carbonate, what weight of each of the following pure reagents would be required to neutralize 25 ml of the hydrochloric acid solution? (a) NaHCO3. (b) KOH, (c) Ba(OH)2• (d) Cao.
4.) If 25.00 ml of a sodium hydroxide solution required 40.00 ml of a sulfuric acid solution in a titration, and 25.00 ml of the sulfuric acid solution were required in the titration of 0.3060 g of pure sodium carbonate, what was the normality of the sodium hydroxide solution?
5.) If 25.00 ml of a sulfuric acid solution were found to be equivalent to 20.50 ml of a sodium hydroxide solution, and 35.00 ml of the sodium hydroxide solution were found to be equivalent to 0.7140 g of pure potassium biphthalate, what weight of barium sulfate could be produced from 50.00 ml of the sulfuric acid solution?
Step by step
Solved in 3 steps
