1. What type of test was used to analyze these data 2. what sample size of this study 3. what is the population mean forgiveness score 4. What is the sample mean forgiveness score 5. what is the critical value of this t
1. What type of test was used to analyze these data 2. what sample size of this study 3. what is the population mean forgiveness score 4. What is the sample mean forgiveness score 5. what is the critical value of this t
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
1. What type of test was used to analyze these data
2. what
3. what is the population
4. What is the sample mean forgiveness score
5. what is the critical value of this t

Transcribed Image Text:### Statistical Analysis Report
#### One-Sample Statistics
- **Variable:** Forgive
- **Sample Size (N):** 15
- **Mean:** 6.4000
- **Standard Deviation:** 0.91026
- **Standard Error Mean:** 0.23503
#### One-Sample Test
- **Test Value:** 5
| **Statistic** | **Value** |
|---------------|-----------|
| **t** | 5.957 |
| **Degrees of Freedom (df)** | 14 |
| **Significance (2-tailed)** | 0.000 |
| **Mean Difference** | 1.40000 |
| **95% Confidence Interval of the Difference** | |
| **Lower** | 0.8959 |
| **Upper** | 1.9041 |
**Explanation:**
The report presents the results of a one-sample t-test conducted to compare the mean of a sample dataset labeled as "forgive" against a test value of 5. With a sample size of 15, the mean is calculated as 6.4000 with a standard deviation of 0.91026. The statistical test shows a t-value of 5.957, with 14 degrees of freedom, yielding a highly significant result (p-value < 0.001). The 95% confidence interval for the mean difference (1.40000) ranges from 0.8959 to 1.9041, suggesting that the test result is statistically significant and different from the test value.
Expert Solution

Step 1: Providing given information
From the given summary table
sample size n=15
Mean=6.4000
standard deviation =0.91206
standard error mean = 0.23503
t statistic value =5.957
df=14
significant level =0.05
Mean difference =1.40000
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