1. What mass of solid Lanthanum (III) oxalate nonahydrate { La2 ( C2O4 )3 ∙ 9 H2O } can be obtained from 650 mL of 0.0170 M aqueous solution of LaCl3 by adding a stoichiometric amount of sodium oxalate? 2. Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloric acid. 2Al + 6HCl → Al2Cl6 + 3H2 3. What mass of ZnCl2 can be prepared from the reaction of 3.27 grams of zinc with 3.30 grams of HCl? Zn +2HCl → ZnCl2 + H2 4. How many milliliters of 0.200 M NH2OH are needed to react with 12.0 mL of 0.550 M FeCl3? FeCl3 + 3NH4OH Fe(OH)3 + 3NH4Cl
1. What mass of solid Lanthanum (III) oxalate nonahydrate { La2 ( C2O4 )3 ∙ 9 H2O } can be obtained from 650 mL of 0.0170 M aqueous solution of LaCl3 by adding a stoichiometric amount of sodium oxalate? 2. Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloric acid. 2Al + 6HCl → Al2Cl6 + 3H2 3. What mass of ZnCl2 can be prepared from the reaction of 3.27 grams of zinc with 3.30 grams of HCl? Zn +2HCl → ZnCl2 + H2 4. How many milliliters of 0.200 M NH2OH are needed to react with 12.0 mL of 0.550 M FeCl3? FeCl3 + 3NH4OH Fe(OH)3 + 3NH4Cl
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. What mass of solid Lanthanum (III) oxalate nonahydrate { La2 ( C2O4 )3 ∙ 9 H2O } can be obtained from 650 mL of 0.0170 M aqueous solution of LaCl3 by adding a stoichiometric amount of sodium oxalate?
2. Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloric acid.
2Al + 6HCl → Al2Cl6 + 3H2
3. What mass of ZnCl2 can be prepared from the reaction of 3.27 grams of zinc with 3.30 grams of HCl?
Zn +2HCl → ZnCl2 + H2
4. How many milliliters of 0.200 M NH2OH are needed to react with 12.0 mL of 0.550 M FeCl3?
FeCl3 + 3NH4OH Fe(OH)3 + 3NH4Cl
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