1. What is the time complexity of the following function? def my_function(my_list, element):        first_item = 0        last_item = len(my_list) - 1        is_found = False        while first_item <= last_item and not is_found:              mid = (first_item + last_item)//2               if my_list[mid] == element:                    is_found = True              else:                     if element < mid:                            last_item = mid - 1                     else:                             first_item = mid + 1         return is_found Group of answer choices a) O(1) b) O(logn) c) O(n) d) O(nlogn)   2. Here is the comparison for asymptotic growth rate: (logn) < (n) < (nlogn) < (n^2) < (n^3) < (2^n) Group of answer choices a) True b) False

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