And which is the reducing agent? 1.) What cell notation explains a voltaic cell comprised of the half reactions below?Fe3+ (aq) + e → Fe²* (aq)F2 (g) + 2 e →→ 2 F (aq)E°red = 0.770 VE°red = 2.866 VI. Fe2* (aq) | Fe+ (aq) || F2(g) F (aq)II. Fe (s) | Fe²* (aq) || Fe³* (aq), F2 (g) | F° (aq) | C(s)III. Pt (s) | Fe³* (aq), Fe²* (aq), F2 (g) || F* (aq) | C(s)IV. Pt (s) | Fe2* (aq), Fe³+ (aq) || F (aq), |F2 (g) | C (s)

Given Half Cell reaction Oxidation Half cell Fe3+ (aq) + e- → Fe2+ (aq)reduction Half cellF2 + 2e-…

1.) What cell notation explains a voltaic cell comprised of the half reactions below? Fe* (aq) + e → Fe2* (aq) F2 (g) +2 e → 2F (aq) E°red = 0.770 V E°red = 2.866 V I. Fe2* (aq) | Fe+ (aq) || F2(g) F (aq) II. Fe (s) | Fe2* (aq) || Fe³+ (aq), F2 (g) | F (aq) | C(s) III. Pt (s) | Fe³* (aq), Fe2* (aq), F2 (g) || F* (aq) | C(s) IV. Pt (s) | Fe2* (aq), Fe³* (aq) || F (aq), |F2 (g)| C (s)

1.) What cell notation explains a voltaic cell comprised of the half reactions below? Fe* (aq) + e → Fe2* (aq) F2 (g) +2 e → 2F (aq) E°red = 0.770 V E°red = 2.866 V I. Fe2* (aq) | Fe+ (aq) || F2(g) F (aq) II. Fe (s) | Fe2* (aq) || Fe³+ (aq), F2 (g) | F (aq) | C(s) III. Pt (s) | Fe³* (aq), Fe2* (aq), F2 (g) || F* (aq) | C(s) IV. Pt (s) | Fe2* (aq), Fe³* (aq) || F (aq), |F2 (g)| C (s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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