1. Using the DC circuit trainer, connect the circuit shown in Fig. (2). take E =10V, R1=822 and R2 1002. Use CDR to calculate currents of "R, , R2. Current Divider Rule The Current Divider Rule (CDR) states that the current through one of two parallel branches is equal to the resistance of the other branch divided by the sum of the resistances of the two parallel branches and multiplied by the total current entering the two parallel branches in figure(2). That is, I E R, R I,

1. Using the DC circuit trainer, connect the circuit shown in Fig. (2). take E =10V, R1=822 and R2 1002. Use CDR to calculate currents of "R, , R2. Current Divider Rule The Current Divider Rule (CDR) states that the current through one of two parallel branches is equal to the resistance of the other branch divided by the sum of the resistances of the two parallel branches and multiplied by the total current entering the two parallel branches in figure(2). That is, I E R, R I,

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

complete the table
A series circuit has a total resistance of 19 ohms and a current flow of 12 A. What is the applied voltage? Select one: a. 1.583 b. .631 c. 228 d. 410
Please answer g
Use Kirchoff's Law to solve for all the voltage drops and branch currents. R1 R4 100 2 70 0 ww ww R2 Vs2 225 2 15V R5 125 Q ww Vs1 20V R3 Vs3 25 Q 6V ww ww
Refer to the following circuit diagram. Find the current Is1 supplied by source E₁. and current Is2 supplied by E2. E₁ 130V Ist A Z₁ 3352 N Z₂ 1052 B D Z₁ 2402 Z 502 C Isz E₂ 110V
The lead storage batteries "A" and "B" are connected in parallel. "A" hasan open circuit voltage of 12 V and an internal resistance of 0.2 ohm.Battery "B" has an open circuit voltage of 12.2 V and an internalresistance of 0.3 ohm. If the two batteries together deliver power to a0.5-ohm power resistor. Neglecting effects of temperature, how muchcurrent is contributed by battery "A"?
Three resistors are connected in parallel namely R1, R2 and R3. It is impressed by a source voltage of 120V. If R1 receives 15W while R2 carries a current if 100mA, what should be the value of resistance R3 if the power supplied by the voltage source is 60W? a. 364.4 ohmsb. 436.4 ohmsc. 43.64 ohmsd. none of these
Determine the Branch Currents using Mesh Currents: a.) Branch ab b.) Branch ac c.) Branch bc NOTE: The unit of resistance is in ohms and the unit of the voltage supply is in volts.
For the circuit shown, select the values of R1, R2 & R3 so that: y11=0.006 mho, y12 =y21=-0.001 mho & y22=0.003 mho I R2 I2 V1 R1 R3 V2 400 ohm, 500 ohm, and 200 ohm 200 ohm, 400 ohm, and 500 ohm 200 ohm, 1000 ohm, and 500 ohm 400 ohm, 1000 ohm, and 400 ohm
LO: 1, 2, 4,5,6: Figure shows the resistors from the previous two examples wired in a differentway—a combination of series and parallel. We can consider R1 to be the resistance of wiresleading to R2 and R3. (a) Find the total resistance. (b) What is the IR drop in R1? (c) Find thecurrent I2 through R2. (d) What power is dissipated by R2?
= 200 N are connected such tha Four resistors, R1 = 100 N, R2 = 250 N, R3 = 350 N and R4 the parallel combination of R, and R2 is connected in series with the parallel combination c R3 and R4. The series-parallel combination is then connected across a 24 V DC power suppl A. Draw the schematic diagram and label the circuit elements. B. Calculate the equivalent resistance of the circuit. (Ans. Req C. Find the total current of the circuit, the voltage across each resistor and the current throug each resistor. = 198. 7013 Q)
FIND THE CURRENT, VOLTAGE AND POWER FOR R1,R2,R3,AND R4.