1. Use the algorithm described in our course materials (videos) that takes a CFG and converts it into a CNF grammar that generates the same language as the original grammar, except possibly for the string A, to answer the following question. As part of your answer, you should say which variables are nullable, and you should give the appropriate grammar after each step of the algorithm. There are four steps. Give a CFG (context-free grammar) in CNF (Chomsky Normal Form) that generates the same language, except possibly for the string A, as the following grammar: S → AB A → abA|A B → bBb| bb
1. Use the algorithm described in our course materials (videos) that takes a CFG and converts it into a CNF grammar that generates the same language as the original grammar, except possibly for the string A, to answer the following question. As part of your answer, you should say which variables are nullable, and you should give the appropriate grammar after each step of the algorithm. There are four steps. Give a CFG (context-free grammar) in CNF (Chomsky Normal Form) that generates the same language, except possibly for the string A, as the following grammar: S → AB A → abA|A B → bBb| bb
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:1. Use the algorithm described in our course materials (videos) that takes a
CFG and converts it into a CNF grammar that generates the same language
as the original grammar, except possibly for the string A, to answer the
following question. As part of your answer, you should say which variables
are nullable, and you should give the appropriate grammar after each step of
the algorithm. There are four steps.
Give a CFG (context-free grammar) in CNF (Chomsky Normal Form) that
generates the same language, except possibly for the string A, as the following
grammar:
S
АВ
→ abA|A
→ bBb|bb
A
B
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