1. Two transverse waves travel through a taut string. The speed of each wave if v= 25.00 m/s. A plot of the vertical position as a function of the horizontal position is shown below for the time t=0.00s. y(m) Y₂(x, 1) = Y/₁(x, 1) KA V₁max 4 V2max 3 = 2 1 0 -1 0 2 4 6 a) What is the wave length of each wave? -2 ^₁ ^₂= b) What is the frequency of each wave? f₁ = Hz -3 -4 m m f₂ = Hz c) What is the maximum vertical speed of the oscillating particles of each string? m/s 8 m/s 10 12 14 16 x(m) 18 20

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Chapter1: Units, Trigonometry. And Vectors
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1. Two transverse waves travel through a taut string. The speed of each wave if v= 25.00 m/s. A plot of
the vertical position as a function of the horizontal position is shown below for the time f = 0.00s.
Y₂(x,1)
=
Vimax
V2max
y(m) 4
4
3
=
Y/₁(x, t)
AMA
=
2
1
a) What is the wave length of each wave?
^₁
✔m
1₂
b) What is the frequency of each wave?
f₁ =
Hz
0
-1
-2
0 2 4 6 8 10 12 14 16 18 20
f₂ =
Hz
c) What is the maximum vertical speed of the oscillating particles of each string?
m/s
m/s
m
x(m)
Transcribed Image Text:1. Two transverse waves travel through a taut string. The speed of each wave if v= 25.00 m/s. A plot of the vertical position as a function of the horizontal position is shown below for the time f = 0.00s. Y₂(x,1) = Vimax V2max y(m) 4 4 3 = Y/₁(x, t) AMA = 2 1 a) What is the wave length of each wave? ^₁ ✔m 1₂ b) What is the frequency of each wave? f₁ = Hz 0 -1 -2 0 2 4 6 8 10 12 14 16 18 20 f₂ = Hz c) What is the maximum vertical speed of the oscillating particles of each string? m/s m/s m x(m)
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