1. Two point charges, QA = +8 µC and QB = -5 µC, are separated by a distance r= 10 cm. What is the magnitude of the electric force? 10 cm A B Known Charge A (q.) = +8 µC = +8 x 10° C Charge B (qg) = -5 µC = -5 x 10ª C k = 9 x 10° Nm²c The distance between charge A and B () = 10 cm = 0.1 m Answer: 4 x 10* N F=k (sx10-)(ix10-) 36N (0.1 )² 2. Three charged particles are arranged in a line as shown in figure below. Charge A = -5 µC, charge B = +10 µC and charge C = -12 µC. A 6 cm 4 сm B Known Charge A (g.) = -5 µC = -5 x 10° C Charge B (q,) = +10 uC = +10 x 10° c Charge C (q.) = -12 µC = -12 x 10° c k = 9 x 10° Nm'c The distance between particle A andB (ran) = 6 cm = 0.06 m = 6 x 10² m The distance between particle B and C (re) = 4 cm = 0.04 m = 4 x 10° m a) Find the magnitude and the direction of net electrostatic force on particle A Answer: 71 N Rightward b) Find the magnitude and the direction of net electrostatic force on particle B Answer: 550 N Rightward 3. +Q1 = 10 µC, +Q2 = 50 µC and Q3 = +90µC are separated as shown in the figure below. cm 6 cm Q2 Qs Known Charge 1 (q1) = +10 µC = +10 x 10° C Charge 2 (q2) = +50 µC = +50 x 10° C Charge 3 (q3) = +90 µC = +90 x 10* C The distance between charge 1 and 2 (r12) = 2 cm = 0.02 m = 2 x 10° m The distance between charge 2 and charge 3 (r23) = 6 cm = 0.06 m = 6 x 10° m a) Find the magnitude and the direction of net electrostatic force on particle 2 Answer: 0N (no direction) b) Find the magnitude and the direction of net electrostatic force on particle 1 Answer: 12,616 N Leftward
1. Two point charges, QA = +8 µC and QB = -5 µC, are separated by a distance r= 10 cm. What is the magnitude of the electric force? 10 cm A B Known Charge A (q.) = +8 µC = +8 x 10° C Charge B (qg) = -5 µC = -5 x 10ª C k = 9 x 10° Nm²c The distance between charge A and B () = 10 cm = 0.1 m Answer: 4 x 10* N F=k (sx10-)(ix10-) 36N (0.1 )² 2. Three charged particles are arranged in a line as shown in figure below. Charge A = -5 µC, charge B = +10 µC and charge C = -12 µC. A 6 cm 4 сm B Known Charge A (g.) = -5 µC = -5 x 10° C Charge B (q,) = +10 uC = +10 x 10° c Charge C (q.) = -12 µC = -12 x 10° c k = 9 x 10° Nm'c The distance between particle A andB (ran) = 6 cm = 0.06 m = 6 x 10² m The distance between particle B and C (re) = 4 cm = 0.04 m = 4 x 10° m a) Find the magnitude and the direction of net electrostatic force on particle A Answer: 71 N Rightward b) Find the magnitude and the direction of net electrostatic force on particle B Answer: 550 N Rightward 3. +Q1 = 10 µC, +Q2 = 50 µC and Q3 = +90µC are separated as shown in the figure below. cm 6 cm Q2 Qs Known Charge 1 (q1) = +10 µC = +10 x 10° C Charge 2 (q2) = +50 µC = +50 x 10° C Charge 3 (q3) = +90 µC = +90 x 10* C The distance between charge 1 and 2 (r12) = 2 cm = 0.02 m = 2 x 10° m The distance between charge 2 and charge 3 (r23) = 6 cm = 0.06 m = 6 x 10° m a) Find the magnitude and the direction of net electrostatic force on particle 2 Answer: 0N (no direction) b) Find the magnitude and the direction of net electrostatic force on particle 1 Answer: 12,616 N Leftward
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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in the image is my assignment. I just want to know if the boxed answer is correct, for problem 1, and whether or not the bolded answers for questions 2 and 3 are correct.
Transcribed Image Text:1. Two point charges, QA = +8 µC and QB = -5 µC, are separated by a distance r= 10 cm.
What is the magnitude of the electric force?
10 cm
B
A
Кnown
Charge A (g.) = +8 µC = +8 x 10°C
Charge B (9.) = -5 µC = -5 x 10°C
k= 9 x 10° Nm?c
The distance between charge A and B (rAR) = 10 cm = 0.1 m
Answer: 4 x 10° N
(sx10-6)(ix10-6)
(0.1)2
F=k
=(9x10)
36N
2. Three charged particles are arranged in a line as shown in figure below. Charge A = -5 µC,
charge B = +10 µC and charge C = -12 µC.
6 cm
4 cm
A
B
Known
Charge A (q,) = -5 µC = -5 x 10° C
Charge B (q) = +10 µC = +10 x 10° c
Charge C (g.) = -12 µC = -12 x 10° C
k = 9 x 10° Nm²c
The distance between particle A and B (r.e) = 6 cm = 0.06 m = 6 x 102 m
The distance between particle B and C (re) = 4 cm = 0.04 m = 4 x 102 m
a) Find the magnitude and the direction of net electrostatic force on particle A
Answer: 71 N Rightward
b) Find the magnitude and the direction of net electrostatic force on particle B
Answer: 550 N Rightward
3. +Q1 = 10 uC, +Q2 = 50 µC and Q3 = +90uC are separated as shown in the figure below.
2 cm
6 cm
Q1
Q2
Known
Charge 1 (q1) = +10 µC = +10 x 10° c
Charge 2 (q2) = +50 µC = +50 x 10° c
Charge 3 (93) = +90 uC = +90 x 10° C
The distance between charge 1 and 2 (r12) = 2 cm = 0.02 m = 2 x 102 m
The distance between charge 2 and charge 3 (r23) = 6 cm = 0.06 m = 6 x 10° m
a) Find the magnitude and the direction of net electrostatic force on particle 2
Answer: 0N (no direction)
b) Find the magnitude and the direction of net electrostatic force on particle 1
Answer: 12,516 N Leftward
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