1. Two point-charges Q₁ and Q₂ are 3 m apart, and their total charge is 21 µC. If the force of repulsion between them is 0.09789 N, what are magnitudes of the two charges by following the steps below? (a) Q₁ + Q₂ (b) Q₁ X Q₂ = Use Coulomb's Law to calculate the product of the two charges. X C² (c) {Q₁, Q₂} 2.1X10 = = -5 (c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. с Enter the answer with curly brackets as {Q₁,Q₂} where Q₁ is the smaller charge and Q₂ is the larger charge. X
1. Two point-charges Q₁ and Q₂ are 3 m apart, and their total charge is 21 µC. If the force of repulsion between them is 0.09789 N, what are magnitudes of the two charges by following the steps below? (a) Q₁ + Q₂ (b) Q₁ X Q₂ = Use Coulomb's Law to calculate the product of the two charges. X C² (c) {Q₁, Q₂} 2.1X10 = = -5 (c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. с Enter the answer with curly brackets as {Q₁,Q₂} where Q₁ is the smaller charge and Q₂ is the larger charge. X
Related questions
Question
Answer B & C please!

Transcribed Image Text:1. Two point-charges Q₁ and Q₂2 are 3 m apart, and their total charge is 21 µC. If the force of repulsion
between them is 0.09789 N, what are magnitudes of the two charges by following the steps below?
(a) Q₁ + Q₂ =
1
2.1X10
C
Use Coulomb's Law to calculate the product of the two charges.
(b) Q₁ X Q₂ =
C²
(c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two
possible solutions.
Enter the answer with curly brackets as {Q₁,Q2} where Q₁ is the smaller charge and Q₂ is the larger
charge.
(c) {Q₁, Q₂} =
X
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 5 steps with 5 images
