1. Two point charges are located on the x-axis as shown, a +2 µC charge at x = -5 cm, and a - 2µC charge at x =+5 cm. (a) Calculate the electric potential at the origin, x= y = 0 cm. (b) For what values of x and y would the electric potential be the same as at the origin? (c) Based upon this equipotential line, what direction should the Electric field be in along this line? (d) If another point charge is placed at y =+5 cm, find the electric potential energy of this particle if it has a total charge of +2 nC.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
Please answer question (d)
1. Two point charges are located on the x-axis as shown, a +2 µC charge at x = -5 cm, and a -
2µC charge at x=+5 cm.
(a) Calculate the electric potential at the origin, x=y = 0 cm.
(b) For what values of x and y would the electric potential be the same as at the origin?
(c) Based upon this equipotential line, what direction should the Electric field be in along this line?
(d) If another point charge is placed at y =+5 cm, find the electric potential energy of this particle if it has
a total charge of +2 nC.
Transcribed Image Text:1. Two point charges are located on the x-axis as shown, a +2 µC charge at x = -5 cm, and a - 2µC charge at x=+5 cm. (a) Calculate the electric potential at the origin, x=y = 0 cm. (b) For what values of x and y would the electric potential be the same as at the origin? (c) Based upon this equipotential line, what direction should the Electric field be in along this line? (d) If another point charge is placed at y =+5 cm, find the electric potential energy of this particle if it has a total charge of +2 nC.
Expert Solution
Step 1
Electric potential = 14TE0xQr
Step 2
(a)
Electric potential at origin due to two charges
V0,0=14TTE02×10-65×10-2+2×10-65×10-2=14Ttɛ02x2x10-65x10-2=9×1094×10-65x10-
2=7.2×105V
(b)
Let V(x,y)=V(0,0).
14TE02×10-6x+0.052+y2+2×10-6x-0.052+y2=14T1E02×2×10-65×10-21x+0.052+y2+1x-
0.052+y2=25x10-2
The shape of this equipotential line is plotted below
2.
10°
0,04
0.02
-O DB
-0 06
-0 04
-0 02
0 02
0 04
0 06
0.02
-0 04
(c) The electric field will be perpendicular to the red line
Step 3
According to Bartleby guidelines only three paerts of a question can be answered at once.
Please post the remaining questions separately.
Rate this solution
Transcribed Image Text:Expert Solution Step 1 Electric potential = 14TE0xQr Step 2 (a) Electric potential at origin due to two charges V0,0=14TTE02×10-65×10-2+2×10-65×10-2=14Ttɛ02x2x10-65x10-2=9×1094×10-65x10- 2=7.2×105V (b) Let V(x,y)=V(0,0). 14TE02×10-6x+0.052+y2+2×10-6x-0.052+y2=14T1E02×2×10-65×10-21x+0.052+y2+1x- 0.052+y2=25x10-2 The shape of this equipotential line is plotted below 2. 10° 0,04 0.02 -O DB -0 06 -0 04 -0 02 0 02 0 04 0 06 0.02 -0 04 (c) The electric field will be perpendicular to the red line Step 3 According to Bartleby guidelines only three paerts of a question can be answered at once. Please post the remaining questions separately. Rate this solution
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Knowledge Booster
Electric field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON