E - - ON10N 16 10 e 5.76 x 10N/CF. - TH )- 0N10N .ON 10-1c 8.2 x 10N8:28 93Z lecture 1 electricity..HAW:1. Three point charges are placed at the coners of an equilateral triangle, asshown in Figure.a.00 e0.600 m3.00 c6.00 uCCalculate the net electric force experienced by (a) the 9.00 uC charge, and(b) The - 6.00 uC charge.2. Two tiny conducting balls of identical mass m and identical charge q hang fromnon-conducting threads of length 1. Each ball forms an angle e with the verticalaxis, as shown in Figure.Show that, at equilibrium, the separation between the balls is= (2neomgElectric Field:* An electric charge q produces an electric field everywhere.* The electric field Ē is defined as:E = limg-0- 90 + Positive test charge (infinitesimally small).* the charge g creates an electric field Ē which exerts a force F= q,Ē on a test charge* the electric field at a distance r from a point charge q is given by4mE, r* superposition principleThe total electric field due to a group of charges is equal to the vector sum of theelectric fields of individual charges:Example: In the classical model of the hydrogen atom, the electron revolves around theproton with a radius of r= 0.53 x 10 1°m. The magnitude of the charge of theelectron and proton is e-1.6 x 10 "C.(a) What is the magnitude of the electric force between the proton and the electron?(b) What is the magnitude of the electric field due to the proton at r?(c) What is ratio of the magnitudes of the electrical and gravitational force betweenelectron and proton? Does the result depend on the distance between the proton andthe electron?(d) In light of your calculation in (b). explain why electrical forces do not influencethe motion of planets.Solution:(a) The magnitude of the force is given by-8.2 x 10" N(0.53N L0- m)(b) The magnitude of the electrie field due to the proton is given by(9.0 x 10°N (1.6 x 10-1"C)(0.saN o m)E5.76 x 10N/C...

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1. Three point charges are placed at the corners of an equilateral triangle, as shown in Figure. 0.600 m 3.00 C 6.00 Ie Calculate the net electric force experienced by (a) the 9.00 uC charge, and (b) The - 6.00 C charge.

1. Three point charges are placed at the corners of an equilateral triangle, as shown in Figure. 0.600 m 3.00 C 6.00 Ie Calculate the net electric force experienced by (a) the 9.00 uC charge, and (b) The - 6.00 C charge.

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E - - ON10N 16 10 e 5.76 x 10N/C
F. - TH )- 0N10N .ON 10-1c 8.2 x 10N
8:28 93
Z lecture 1 electricity..
HAW:
1. Three point charges are placed at the coners of an equilateral triangle, as
shown in Figure.
a.00 e
0.600 m
3.00 c
6.00 uC
Calculate the net electric force experienced by (a) the 9.00 uC charge, and
(b) The - 6.00 uC charge.
2. Two tiny conducting balls of identical mass m and identical charge q hang from
non-conducting threads of length 1. Each ball forms an angle e with the vertical
axis, as shown in Figure.
Show that, at equilibrium, the separation between the balls is
= (
2neomg
Electric Field:
* An electric charge q produces an electric field everywhere.
* The electric field Ē is defined as:
E = limg-0
- 90 + Positive test charge (infinitesimally small).
* the charge g creates an electric field Ē which exerts a force F= q,Ē on a test charge
* the electric field at a distance r from a point charge q is given by
4mE, r
* superposition principle
The total electric field due to a group of charges is equal to the vector sum of the
electric fields of individual charges:
Example: In the classical model of the hydrogen atom, the electron revolves around the
proton with a radius of r= 0.53 x 10 1°m. The magnitude of the charge of the
electron and proton is e-1.6 x 10 "C.
(a) What is the magnitude of the electric force between the proton and the electron?
(b) What is the magnitude of the electric field due to the proton at r?
(c) What is ratio of the magnitudes of the electrical and gravitational force between
electron and proton? Does the result depend on the distance between the proton and
the electron?
(d) In light of your calculation in (b). explain why electrical forces do not influence
the motion of planets.
Solution:
(a) The magnitude of the force is given by
-8.2 x 10" N
(0.53N L0- m)
(b) The magnitude of the electrie field due to the proton is given by
(9.0 x 10°N (1.6 x 10-1"C)
(0.saN o m)
E
5.76 x 10N/C
...

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