1. Three blocks are connected with massless strings as shown below and pulled by a force F-16 N tothe right on a frictionless surface. m₁ = 7 kg, m₂ = 9 kg, and m² = 12 kg.12m₁Calculate:(a) the acceleration a of the masses,Enter to 2 significant figuresm/s²(b) the tensions in the strings.Enter to 2 significant figuresT₁ =T₂ =a = 0.57m₂Xm3F

GivenForce F=16NMass m1=7kgMass m2=9kgMass m3=12kgThe acceleratrion is given by

1. Three blocks are connected with massless strings as shown below and pulled by a force F-16 N to the right on a frictionless surface. m₁ = 7 kg, m2₂ = 9 kg, and m₂ = 12 kg. 2 m₁ m₂ Calculate: (a) the acceleration a of the masses, Enter to 2 significant figures a = 0.57 m/s² (b) the tensions in the strings. m3 F

1. Three blocks are connected with massless strings as shown below and pulled by a force F-16 N to the right on a frictionless surface. m₁ = 7 kg, m2₂ = 9 kg, and m₂ = 12 kg. 2 m₁ m₂ Calculate: (a) the acceleration a of the masses, Enter to 2 significant figures a = 0.57 m/s² (b) the tensions in the strings. m3 F

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

3. What is the value of the force at 40.0 cm in the diagram below? t =
Two horses on opposite banks of a canal pull a barge moving parallel the banks by means of two horizontal ropes. The tensions in these ropes are F1 = 87 kN and F2 = 233 kN, while the angle between them is 54 degrees. Find the 01 in degrees. Write numerical value only and 2 decimal places. ... 1224 0₂ Ө
Two masses m1=4 Kg and m2=10 Kg are connected with string and pulled with a force F=22 N that makes an angle of 53° with a smooth horizontal surface as shown in the figure. Find the tension in the string in a unit of Newton. F m2 A. None В. 1.891 С. 5.35 D. 3.783 E. 7.565
For figure shown: 100 lb 150 lb 1. Calculate the force of the rope attached at 150-lb. (lb) а. 120 b. None of the above с. 100 d. 130 e. 150 2. Calculate the force of the rope attached at 100-lb. (lb) а. 120 b. 100 с. 130 d. 150 e. none of the above 3. Calculate the acceleration of the 100-lb cylinder. (ft/s) a. 16.10 b. none of the above C. 4.29 d. 6.44 e. 2. 15
Commercial airplanes are sometimes pushed out of the passenger loading area by a tractor. (a) The 1800 kg tractor exerts a force of 1.80 × 104 N backward on the pavement, and the system experiences forces resisting motion that total 2400 N. If the acceleration is 0.170 m/s2, what is the mass of the airplane in kilograms? kg (b) Calculate the force (in N) exerted by the tractor on the airplane, assuming 2250 N of the friction is experienced by the airplane. N
3.8
A bead moves with 0 r = roebt, where ro and b are constants. = w = constant and Find the force F, and Fe of the motion. F, = (b*roeht - roeht ?)f F = 2browet @ F, = (b'eb-roet w?)F Fo = 2brgwe @ %3D F, = (b*eht - roebt w²)f Fo browet o F, = (b'et - roeht p F, = brgwet %3D
Two forces act on a 4.15-kg object: 31.1 N in the +x direction and 68.5 N in the -y direction. What is the amount of the object's acceleration (in m/s )? [3 sig. figs.] Answer. -9.01 What is the direction of the object's acceleration (in degrees counterclockwise from +x) [3 sig. figs.] Answer. 75.2
m/s m kg m¹ unitless J-S c=yx1 1x1 E = E = h x h x c 1
A 700 N police officer is supported by three cables(T, T2 and T3), of which T, and T2 are making angles 0, = 54° and 0, = 33° as shown in Figure. Here T, 700 N, calculate the tensions T, and T2. 02 T1 T2 T3 (a) Tension in string 1, T, (in Newton) = (b) Tension in string 2. T2 (in Newton) =
A 105 N object is supported by three cables(T1, T2 and T3), of which T1 and T2 are making angles O, = 74° and 02 = 37° as shown in Figure. Here T3 = 105 N, calculate the tensions T1 and T2. 01 02 T1 T2 T3 W (a) Tension in string 1, T1 (in Newton) (b) Tension in string 2, T2 (in Newton) =
It is fixed at one end of the D pipe.Collar A can move on pipe D and collar B on pipe A without friction.The general equation for the position of the ring A is SA, the general equation for the velocity of the B ring is VB. The friction coefficient between the C ring and the B pipe is 0.3 .All rings weigh 98.1N .Neglect the weight of the pipes. SA=(20+0.4t2+0.01t4)i+0j VB=0i+(0.3t2+25)j If ?=25°,draw the free body diagram and kinetic diagram for B and C rings for t = 4 s and find the unknown force values. Also calculate the relative acceleration of Rings B and C and the vectorial value of the acceleration of the X-Y axis with respect to the origin.