1. This is a terminal velocity question. The aerodynamic drag on an object traveling through still air is calculated as follows: Fd = 0.5 x p x Cd x A x V 2 where Fd is the drag force (N), p is the air density (kg/m ³), Cd is the coefficient of drag (dimensionless), A is the surface area presented to the airstream (m 2), and V is velocity of the object (m/sec). At terminal velocity, aerodynamic forces (acting upwards on a falling object) are equal to the forces acting downward on the object (due to gravity alone) Given the above, what is the terminal velocity of a 65 kg human falling through still air in a spread arms and legs posture (A = 1.4 m 2, Cd = 0.9, p = 1.27 kg/m 3) ? Provide your answer in miles per hour (mph). You will need to convert your calculated answer, from m/sec to mph. Pick one from the list below. 63.14 28.23 O 92.62 100.00

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1. This is a terminal velocity question. The aerodynamic drag on an object
traveling through still air is calculated as follows:
Fd = 0.5 x p x Cd x Ax V 2
where Fd is the drag force (N), p is the air density (kg/m ³), Cd is the
coefficient of drag (dimensionless), A is the surface area presented to the
airstream (m ²), and V is velocity of the object (m/sec).
At terminal velocity, aerodynamic forces (acting upwards on a falling object)
are equal to the forces acting downward on the object (due to gravity alone)
Given the above, what is the terminal velocity of a 65 kg human falling
through still air in a spread arms and legs posture (A = 1.4 m 2, Cd = 0.9, p =
1.27 kg/m 3) ?
Provide your answer in miles per hour (mph). You will need to convert your
calculated answer, from m/sec to mph.
Pick one from the list below.
63.14
28.23
92.62
O 100.00
Transcribed Image Text:1. This is a terminal velocity question. The aerodynamic drag on an object traveling through still air is calculated as follows: Fd = 0.5 x p x Cd x Ax V 2 where Fd is the drag force (N), p is the air density (kg/m ³), Cd is the coefficient of drag (dimensionless), A is the surface area presented to the airstream (m ²), and V is velocity of the object (m/sec). At terminal velocity, aerodynamic forces (acting upwards on a falling object) are equal to the forces acting downward on the object (due to gravity alone) Given the above, what is the terminal velocity of a 65 kg human falling through still air in a spread arms and legs posture (A = 1.4 m 2, Cd = 0.9, p = 1.27 kg/m 3) ? Provide your answer in miles per hour (mph). You will need to convert your calculated answer, from m/sec to mph. Pick one from the list below. 63.14 28.23 92.62 O 100.00
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