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1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes Compute for the discharge at line 2 Compute for the discharge at line 1 Compute for the discharge at line 4 (BCD) Pipe Diameter Length in (mm) 600 AB BC CD BD DE 450 450 500 600 Q1 = Q3 Q1 = Q2 + Q4 hfr = hf₁ + hf₂ + hf3 hf₂ = hf Q4 = 0.2974 m³/s Q₁ = 0.7663 m³/s Q3 = 0.7663 m³/s Q2 = 0.4689 m³/s m 600 400 450 600 650 1 B 2 C D 3 E

1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes Compute for the discharge at line 2 Compute for the discharge at line 1 Compute for the discharge at line 4 (BCD) Pipe Diameter Length in (mm) 600 AB BC CD BD DE 450 450 500 600 Q1 = Q3 Q1 = Q2 + Q4 hfr = hf₁ + hf₂ + hf3 hf₂ = hf Q4 = 0.2974 m³/s Q₁ = 0.7663 m³/s Q3 = 0.7663 m³/s Q2 = 0.4689 m³/s m 600 400 450 600 650 1 B 2 C D 3 E

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes Compute for the discharge at line 2 Compute for the discharge at line 1 Compute for the discharge at line 4 (BCD) Pipe Diameter Length in (mm) 600 AB BC CD BD DE 450 450 500 600 Q1 = Q3 Q1 = Q2 + Q4 hfr = hf₁ + hf₂ + hf3 hf₂ = hf Q4 = 0.2974 m³/s Q₁ = 0.7663 m³/s Q3 = 0.7663 m³/s Q2 = 0.4689 m³/s m 600 400 450 600 650 1 B 2 C D 3 E
Transcribed Image Text:1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes Compute for the discharge at line 2 Compute for the discharge at line 1 Compute for the discharge at line 4 (BCD) Pipe Diameter Length in (mm) 600 AB BC CD BD DE 450 450 500 600 Q1 = Q3 Q1 = Q2 + Q4 hfr = hf₁ + hf₂ + hf3 hf₂ = hf Q4 = 0.2974 m³/s Q₁ = 0.7663 m³/s Q3 = 0.7663 m³/s Q2 = 0.4689 m³/s m 600 400 450 600 650 1 B 2 C D 3 E
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