1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes Compute for the discharge at line 2 Compute for the discharge at line 1 Compute for the discharge at line 4 (BCD) Pipe Diameter Length in (mm) 600 AB BC CD BD DE 450 450 500 600 Q1 = Q3 Q1 = Q2 + Q4 hfr = hf₁ + hf₂ + hf3 hf₂ = hf Q4 = 0.2974 m³/s Q₁ = 0.7663 m³/s Q3 = 0.7663 m³/s Q2 = 0.4689 m³/s m 600 400 450 600 650 1 B 2 C D 3 E

1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes Compute for the discharge at line 2 Compute for the discharge at line 1 Compute for the discharge at line 4 (BCD) Pipe Diameter Length in (mm) 600 AB BC CD BD DE 450 450 500 600 Q1 = Q3 Q1 = Q2 + Q4 hfr = hf₁ + hf₂ + hf3 hf₂ = hf Q4 = 0.2974 m³/s Q₁ = 0.7663 m³/s Q3 = 0.7663 m³/s Q2 = 0.4689 m³/s m 600 400 450 600 650 1 B 2 C D 3 E

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Time and time related variables in engineering

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Question

1. The total headlost from A to E as shown is 20 m. Use n = 0.011 to all pipes
Compute for the discharge at line 2
Compute for the discharge at line 1
Compute for the discharge at line 4 (BCD)
Pipe
Diameter
Length in
(mm)
600
AB
BC
CD
BD
DE
450
450
500
600
Q1 = Q3
Q1 = Q2 + Q4
hfr = hf₁ + hf₂ + hf3
hf₂ = hf
Q4 = 0.2974 m³/s
Q₁ = 0.7663 m³/s
Q3 = 0.7663 m³/s
Q2 = 0.4689 m³/s
m
600
400
450
600
650
1 B
2
C
D 3
E

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Step 4: Determine the discharge in each line.

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