1. The temperature at the point (r, y) on an unevenly heated plate is given by T = f(r, y) = 100+ 5a? + 15x + 10y?. Both r and y are in centimeters and T is in degrees centigrade. What is the maximum directional derivative at the point (2,1)?

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Author:James Stewart
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Chapter1: Functions And Models
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### Problem 1: Temperature Distribution on a Heated Plate

The temperature at a point \((x, y)\) on an unevenly heated plate is described by the function:

\[ T = f(x, y) = 100 + 5x^2 + 15x + 10y^2 \]

where:
- \(x\) and \(y\) are measured in centimeters,
- \(T\) is the temperature in degrees centigrade.

**Objective:**

Determine the maximum directional derivative at the point \((2, 1)\).

**Explanation:**

To find the maximum directional derivative, you must calculate the gradient of the temperature function \( \nabla T \) at the given point. The magnitude of this gradient gives the rate of maximum increase of the function, which corresponds to the maximum directional derivative.
Transcribed Image Text:### Problem 1: Temperature Distribution on a Heated Plate The temperature at a point \((x, y)\) on an unevenly heated plate is described by the function: \[ T = f(x, y) = 100 + 5x^2 + 15x + 10y^2 \] where: - \(x\) and \(y\) are measured in centimeters, - \(T\) is the temperature in degrees centigrade. **Objective:** Determine the maximum directional derivative at the point \((2, 1)\). **Explanation:** To find the maximum directional derivative, you must calculate the gradient of the temperature function \( \nabla T \) at the given point. The magnitude of this gradient gives the rate of maximum increase of the function, which corresponds to the maximum directional derivative.
Expert Solution
Step 1

Given

f=100+5x2+15x+10y2gradient of ff=fxi+fyj     =10x+15i+20yjAt (2, 1)f=10x+15i+20yj     =35i+20j

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