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1. The tangents of a simple curve have bearings N75°12'E and S78°36'E respectively. What is the central angle of the curve? a. 29°18' b. 27°51' c. 22°39' d. 26°12'

1. The tangents of a simple curve have bearings N75°12'E and S78°36'E respectively. What is the central angle of the curve? a. 29°18' b. 27°51' c. 22°39' d. 26°12'

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Read and understand each of the following questions. Solve it in a clean short bond paper. Show your complete and neat solutions. Finalize your answers in a box. SIMPLE CURVE 1. The tangents of a simple curve have bearings N75°12'E and S78°36'E respectively. What is the central angle of the curve? a. 29°18' b. 27°51' c. 22°39' d. 26°12' 2. A circular curve has the following data: Azimuth of back tangent = 205° Azimuth of forward tangent = 262° Middle ordinate = 5.80m Find the length of the tangent c. 22.66 m d. 24.88 m a. 25.99 m b. 23.77 m 3. The tangents of a simple curve have bearings N75°12'E and S78°36'E respectively and D = 4°, with PC at Sta 27 + 360. Calculate the deflection angles for the circular curves at the stationings. COMPOUND CURVE 4. Station PT of a compound curve is at 15+ 480, I, = 30°,I2 = 36°,D1 = 4°, and D2 = 5°. What is the stationing of PCC? Use arc basis. c. 15 + 325.28 d. 15 + 342.50 a. 15+ 319.63 b. 15+ 336.14 5. A compound curve has the following data: I, = 28°, I2 = 31°, D, = 3°, and D2 = 4°. Find the stationing of PCC. Use Sta PI = 30 + 120.5. 30+ 110.73 b. 30+ 118.46 c. 30 + 114.88 d. 30 + 106.97 a.
Transcribed Image Text:Read and understand each of the following questions. Solve it in a clean short bond paper. Show your complete and neat solutions. Finalize your answers in a box. SIMPLE CURVE 1. The tangents of a simple curve have bearings N75°12'E and S78°36'E respectively. What is the central angle of the curve? a. 29°18' b. 27°51' c. 22°39' d. 26°12' 2. A circular curve has the following data: Azimuth of back tangent = 205° Azimuth of forward tangent = 262° Middle ordinate = 5.80m Find the length of the tangent c. 22.66 m d. 24.88 m a. 25.99 m b. 23.77 m 3. The tangents of a simple curve have bearings N75°12'E and S78°36'E respectively and D = 4°, with PC at Sta 27 + 360. Calculate the deflection angles for the circular curves at the stationings. COMPOUND CURVE 4. Station PT of a compound curve is at 15+ 480, I, = 30°,I2 = 36°,D1 = 4°, and D2 = 5°. What is the stationing of PCC? Use arc basis. c. 15 + 325.28 d. 15 + 342.50 a. 15+ 319.63 b. 15+ 336.14 5. A compound curve has the following data: I, = 28°, I2 = 31°, D, = 3°, and D2 = 4°. Find the stationing of PCC. Use Sta PI = 30 + 120.5. 30+ 110.73 b. 30+ 118.46 c. 30 + 114.88 d. 30 + 106.97 a.
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