1. The system in right figure consists of a water reservoir with a layer of compressed air above the water and a large pipe and nozzle. The pressure of the air is 50 psig, and the effects of friction can be neglected. What is the velocity of the water flowing out through the nozzle? 50 psig 30 ft
1. The system in right figure consists of a water reservoir with a layer of compressed air above the water and a large pipe and nozzle. The pressure of the air is 50 psig, and the effects of friction can be neglected. What is the velocity of the water flowing out through the nozzle? 50 psig 30 ft
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
100%
can you please solve question 1
Transcribed Image Text:1. The system in right figure consists of a water reservoir with a
layer of compressed air above the water and a large pipe and nozzle.
The pressure of the air is 50 psig, and the effects of friction can be
neglected. What is the velocity of the water flowing out through the
nozzle?
50 psig
2. The tank in right figure is cylindrical and has a vertical axis. Its
horizontal cross-sectional area is 100 ft². The hole in the bottom has
a cross-sectional area of 1 ft². The interface between the gasoline and the
water remains perfectly horizontal at all times. That interface is now 10 ft
above the bottom. How soon will gasoline start to flow out the bottom?
Assume frictionless flow.
30 ft
10 ft
10 ft
1
Gasoline
Water
iiili
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question
can u explain to me why this solution isnt correct?
![The text presents a fluid mechanics problem involving Bernoulli’s equation:
1. **Initial Assumptions:**
- The system is open to the atmosphere, so \( P_1 = P_2 = 0 \).
- The inlet velocity (\( V_{\text{inlet}} \)) is 0 and is not provided.
2. **Bernoulli's Equation:**
\[
\frac{P_1}{\rho} + gz_1 + \frac{V_1^2}{2} = \frac{P_2}{\rho} + gz_2 + \frac{V_2^2}{2} + F_{\text{friction}}
\]
- Friction term (\( F_{\text{friction}} \)) is crossed out, indicating negligible friction.
3. **Simplified Equation:**
\[
\left(\frac{P_2 - P_1}{\rho}\right) + \left(\frac{V_2^2 - V_1^2}{2}\right) + g(z_2 - z_1) = 0
\]
- The terms \(\frac{V_2^2}{2} + g(z_2 - z_1) = 0\) further simplify the equation.
4. **Final Velocity Derivation:**
\[
\frac{V_2^2}{2} = gz_1 \quad \text{where} \quad z_1 = 10 \text{ ft}
\]
- Velocity calculation for water (\( V_2 \)):
\[
V_2(\text{water}) = \sqrt{2gz_1} = \sqrt{\frac{32.2 \text{ ft/s}^2 \times 20 \text{ ft}}{2}} = 25.38 \text{ ft/s}
\]
The final velocity of the water is 25.38 feet per second.](https://content.bartleby.com/qna-images/question/63f5865a-7713-44c4-be73-1c5678c4385b/5f6178af-d42d-490b-833d-4613c862799e/eidefbm_processed.jpeg)
Transcribed Image Text:The text presents a fluid mechanics problem involving Bernoulli’s equation:
1. **Initial Assumptions:**
- The system is open to the atmosphere, so \( P_1 = P_2 = 0 \).
- The inlet velocity (\( V_{\text{inlet}} \)) is 0 and is not provided.
2. **Bernoulli's Equation:**
\[
\frac{P_1}{\rho} + gz_1 + \frac{V_1^2}{2} = \frac{P_2}{\rho} + gz_2 + \frac{V_2^2}{2} + F_{\text{friction}}
\]
- Friction term (\( F_{\text{friction}} \)) is crossed out, indicating negligible friction.
3. **Simplified Equation:**
\[
\left(\frac{P_2 - P_1}{\rho}\right) + \left(\frac{V_2^2 - V_1^2}{2}\right) + g(z_2 - z_1) = 0
\]
- The terms \(\frac{V_2^2}{2} + g(z_2 - z_1) = 0\) further simplify the equation.
4. **Final Velocity Derivation:**
\[
\frac{V_2^2}{2} = gz_1 \quad \text{where} \quad z_1 = 10 \text{ ft}
\]
- Velocity calculation for water (\( V_2 \)):
\[
V_2(\text{water}) = \sqrt{2gz_1} = \sqrt{\frac{32.2 \text{ ft/s}^2 \times 20 \text{ ft}}{2}} = 25.38 \text{ ft/s}
\]
The final velocity of the water is 25.38 feet per second.
Solution
by Bartleby ExpertKnowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY