1. The solids content of a stream water sample is to be determned. The total solids content is determined by placing a portion of the sample into a porcelain evaporating disk, daypay the samples. at 105°C, and igniting the residue by placing the dored sample The followy marses ave recorded : in a muffle furnace of Iod. mass mass of empty dish: 50.326 g f dish and sample: 118.400 g mass of dish and dry solids : to. 437.J mass of dish and ighted solids: 50.383 g a) The total solids content is b). 07 The fixed solids content is The tital volatile solicls content is

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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1. The solids content of a stream water sample is to be determined. The total solids content is
determined by placing a portion of the sample into a porcelan evaporating dish, dayay the sample
at 105°C, and igniting the residue by placing the dired sample in a muffle furnace at 150°C.
The followry merses are recorded i
mass of empty dish: 50.326g
mass of dish and sample: 118. 400 g
mass of dich and dry solros: 10.437.J
mass of dish and ignited solids : 10.383 g
a) The total solids content is
b).
The tital volatile solids content is
07 The fixed solids content is
Transcribed Image Text:1. The solids content of a stream water sample is to be determined. The total solids content is determined by placing a portion of the sample into a porcelan evaporating dish, dayay the sample at 105°C, and igniting the residue by placing the dired sample in a muffle furnace at 150°C. The followry merses are recorded i mass of empty dish: 50.326g mass of dish and sample: 118. 400 g mass of dich and dry solros: 10.437.J mass of dish and ignited solids : 10.383 g a) The total solids content is b). The tital volatile solids content is 07 The fixed solids content is
Expert Solution
Step 1: Data given

Mass of empty dish = W1 = 50.326 gm 

Mass of dish + sample = W2 = 118.400 gm 

Mass of dish and dried sample = W3 = 50.437 gm 

Mass of dish and ihnites solid = W4 = 50.383 gm

Volume of sample V = 118.400- 50.326

V= 68.074 ml


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