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1. The slope of the perpendicular line 3x+6y=2 is a. m' = 2 b. m² d. m' = -2 m' = 2 2. The equation for line pass through (-4,2) and has slop 0 is a. y = -4 b. y = 4 c. y = 2 d. y = 0 3. The equation for vertical line through the given point (-3, 4) is a.x=4 b. x=-3 c. x=-4 d. x=3 4. The equation for horizontal line through the given point (3,-5) is a. y = 3 b. y=-5 c. y=5 d. y=-3

1. The slope of the perpendicular line 3x+6y=2 is a. m' = 2 b. m² d. m' = -2 m' = 2 2. The equation for line pass through (-4,2) and has slop 0 is a. y = -4 b. y = 4 c. y = 2 d. y = 0 3. The equation for vertical line through the given point (-3, 4) is a.x=4 b. x=-3 c. x=-4 d. x=3 4. The equation for horizontal line through the given point (3,-5) is a. y = 3 b. y=-5 c. y=5 d. y=-3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1. The slope of the perpendicular line 3x+6y=2 is = 1/24 d. m' = -2 a.m² =2_b.m' 1/12 c. m' 2. The equation for line pass through a.y=-4 b.y = 4 c. y = 2 (-4,2) and has slop 0 is d. y=0 3. The equation for vertical line through the given point (-3, 4) is a. x = 4 b. x=-3 c. x = -4 d. x=3 4. The equation for horizontal line through the given point (3,-5) is a.y=3 b. y=-5 c. y=5 d. y=-3
Transcribed Image Text:1. The slope of the perpendicular line 3x+6y=2 is = 1/24 d. m' = -2 a.m² =2_b.m' 1/12 c. m' 2. The equation for line pass through a.y=-4 b.y = 4 c. y = 2 (-4,2) and has slop 0 is d. y=0 3. The equation for vertical line through the given point (-3, 4) is a. x = 4 b. x=-3 c. x = -4 d. x=3 4. The equation for horizontal line through the given point (3,-5) is a.y=3 b. y=-5 c. y=5 d. y=-3
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