1. The results of a standard Proctor test are given in the following table. Weight of Moist Soil in the Mold (kg) Trial No. Moisture Content (%) 1.68 9.9 1.71 10.6 12.1 1.77 1.83 13.8 1.86 15.1 1.88 1.87 1.85 17.4 19.4 8 21.2 a) Determine the maximum dry unit weight of compaction and the optimum moisture content. Given: mold volume = 943.3 cm3 b) Determine the void ratio and the degree of saturation at the optimum moisture content. Given: Gs = 2.7. -23 4567 CO

Q: The laboratory test results of standard proctor test are given in the tabl kimum dry unit weight of…

A: γwet=γbulk=wt of soilvolume of soilγdry=γd=wt of soil(1+moisture content)

Q: Following the sieve analysis and the specific gravity of "SAND 1", a hydrometer test was performed…

A: The hydrometer test is used to determine the distribution of soil particle sizes that are smaller…

Q: constant head permeability test is performed on soil that is 2 cm x 2 cm square, and 2.5cm long. The…

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Q: Draw the compaction curve using the following given data from a standard Proctor test. 2. From…

A: Objective: To draw the compaction curve for the given Standard Proctor Test results, and determine…

Q: Following are the results of a field unit weight determination test on the same soil with the sand…

A: Soil compaction is a process in which the soil retains mechanical pressure and is compacted. The…

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

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Q: 1. A soil sample is collected at 20 °C and taken to the laboratory. The sample is in a stainless…

A: A soil sample in stainless steel cylinder is given with the weight of the cylinder and weight of…

Q: Undisturbed soil sample was collected from the filed in Melbourne in steel tube for laboratory…

A: Diameter of the steel tube =  85 mmLength of steel tube= 170 mm (0.17 m)Moisture weight = 1600…

Q: How do i solve problem 6.4 a & b

A: The given data is shown below:

Q: TABLE 2 RESULTS OF ORI TEST Water Content (%) Weight (Kg) 14 1.45 16.5 1.71 18.5 1.87 20 1.88 21…

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Q: Standard Proctor test was conducted on a silty clay soil collected from a proposed construction…

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Q: A sample of sand has the following properties: Moist sand Dry sand Absorption 605 grams 550 grams…

A: solution Given Moist sand Msat=605 gramsDry sand Mdry=550gramsAbsorption =2%so the amount of water…

Q: A sample of field soi! is tested in the laboratory. The results of Standard Proctor test at optimum…

A: Degree of compaction Soil compaction is the process of applying mechanical compaction effort to the…

Q: k₂ for 10 seconds and the water level is 20 cm, the water flowing measured as much as 50 cm3. What…

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Q: A sample of field soil is tested in the laboratory. The results of Standard and Modified Proctor…

A: ASKED: To compute: degree of compaction/relative compaction (R%) at Standard Proctor Test degree of…

Q: The results of a standard Proctor test are given in the following table. Given: Mold volume : 1/30…

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Q: Determine the force in each member of the structure and establish whether the members are in tension…

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Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.