1. The outer diameter of an arrowis nominally 20 cm. The diameter is normally distributed with mean 20cm and standard deviation 1.25 cm. If the actual diameter deviates from the nominal by more than 2 cm and by less than 4 cm, the manufacturer loses 150 pesos. If the difference is more than 5cm, the manufacturer loses 350 pesos. A) Find the maximumdiameter of 95% of the arrows B) Find the minimum diameter of 8% of the arrows C) Find the probability distribution function of the random variable "manufacturer's loss" D) Find the mean and standard deviation of the manufacturer's loss E) How should the standard deviation be adjusted so that there is only loss in 1% of the arrows? 2- The time in seconds it takes to connecta server on a weekdayfollows a Weibull distribution with a = 0.6"and" B = 0.25. At the weekend it has the same distribution with parameters a = 0.24 "and" B = 1. A) Calculate the difference between the mean response time between the week and the weekend. B) Calculate the probability that during the week, the connection takes more than 10 seconds. C) Calculate the probability that on the weekend, the connection takes more than 10 seconds. D) If we have been waiting more than 3 minutes forthe connection, ittakes more than 10 seconds to make a connection. E) What is the maximum time of 90% of the connections?

Q: B125 32 44 5.

A:

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A: Please see the addition below.

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A: Simplifying above equation we get ;

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A: The given expression is;

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A: Answer

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A: The detailed solution is as follows below:

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