1. The number of iterations for the for loop below is: for a in b c d e; do echo $a; done; (a) 1 (b)2 (c) 3 (d)4 (b c d e), the for loop below will print: ${!1st [@] }; do echo $a; done; (b)1 2 3 4 (c) bc de (d)4 3. Given 1st = (b c d e), the number of iterations for the for loop below is: for a in $1st; do echo $a; done; (a) 1 (b)2 (c) 3 2. Given 1st = for a in (a) 0123 (e)none of the above 5. The number of iterations for the for loop below is: for a in 'b c d e'; do echo $a; done; (a) 1 (b)2 (c) 3 (d)4 (e)none of the above (d)4 4. Given 1st= (b c d e), the number of iterations for the for loop below is: for a in ${1st [@] }; do echo $a; done; (a) 1 (b)2 (c) 3 (d)4 (e)none of the above (e)none of the above (e)none of the above
1. The number of iterations for the for loop below is: for a in b c d e; do echo $a; done; (a) 1 (b)2 (c) 3 (d)4 (b c d e), the for loop below will print: ${!1st [@] }; do echo $a; done; (b)1 2 3 4 (c) bc de (d)4 3. Given 1st = (b c d e), the number of iterations for the for loop below is: for a in $1st; do echo $a; done; (a) 1 (b)2 (c) 3 2. Given 1st = for a in (a) 0123 (e)none of the above 5. The number of iterations for the for loop below is: for a in 'b c d e'; do echo $a; done; (a) 1 (b)2 (c) 3 (d)4 (e)none of the above (d)4 4. Given 1st= (b c d e), the number of iterations for the for loop below is: for a in ${1st [@] }; do echo $a; done; (a) 1 (b)2 (c) 3 (d)4 (e)none of the above (e)none of the above (e)none of the above
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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please asnwer right one do not use chatgpt please
![1. The number of iterations for the for loop below is:
for a in b c d e; do echo $a; done;
(a) 1
(b)2
(c) 3
2. Given 1st =
for a in
(a) 0123
3. Given 1st =
for a in
(a) 1
(d)4
(b c d e), the for loop below will print:
${!1st [@] }; do echo $a; done;
(c) b c de
(b)1 2 3 4
(d)4
(b c d e), the number of iterations for the for loop below is:
$1st; do echo $a; done;
(b)2
(c) 3
(e)none of the above
5. The number of iterations for the for loop below is:
for a in 'b c d e'; do echo $a; done;
(a) 1
(b)2
(c) 3
(d)4
(e)none of the above
(d)4
4. Given 1st= (b c d e), the number of iterations for the for loop below is:
for a in ${1st [@] }; do echo $a; done;
(a) 1
(b)2
(c) 3
(d)4
(e)none of the above
(e)none of the above
(e)none of the above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5bad4e48-dad8-4710-a64b-b24b80d1efcf%2Fe3b7ff0a-79f1-4fed-977b-e289cd50cbf1%2F8ss2qiwe_processed.png&w=3840&q=75)
Transcribed Image Text:1. The number of iterations for the for loop below is:
for a in b c d e; do echo $a; done;
(a) 1
(b)2
(c) 3
2. Given 1st =
for a in
(a) 0123
3. Given 1st =
for a in
(a) 1
(d)4
(b c d e), the for loop below will print:
${!1st [@] }; do echo $a; done;
(c) b c de
(b)1 2 3 4
(d)4
(b c d e), the number of iterations for the for loop below is:
$1st; do echo $a; done;
(b)2
(c) 3
(e)none of the above
5. The number of iterations for the for loop below is:
for a in 'b c d e'; do echo $a; done;
(a) 1
(b)2
(c) 3
(d)4
(e)none of the above
(d)4
4. Given 1st= (b c d e), the number of iterations for the for loop below is:
for a in ${1st [@] }; do echo $a; done;
(a) 1
(b)2
(c) 3
(d)4
(e)none of the above
(e)none of the above
(e)none of the above
![31. Assuming ls -1 /home/cs288 returns a string
'drwxr-xr-x+ 1 CS288 CS288 123 Dec 25 2013'
the command to find the file size 123 is
(b)cut -d'' - £4
(e)none of the above
(a)cut -d'' -£3
(d)cut -f' ' -d4
32. Consider a list of file sizes 1st = (1 2 3 4 5), the average file size is computed by:
sum=0; n=${#1st [@] };
(a) for ((i=0;i<n;i++)); do ((sum-sum+1st[i])); done; ((avg=sum/n));
(b) for x in ${lst[@]}; do sum='expr $sum + $x'; done; avg='expr $sum / $n';
(c) for x in ${!lst[@]}; do ((sum-sum+lst[x])); done; ((avg=sum/n));
(d) all of the above
(e) none of the above
33. To list commands that start with
(a) ls /bin | grep ^a
(c) ls /bin | grep a
(e) none of the above
34. To list commands that end with 'a' under /bin you type
(b) ls /bin | grep a*
(d) ls /bin | grep as
(a) ls /bin | grep ^a
(c) ls /bin | grep a
(e) none of the above
'a' under /bin you type
(b) ls /bin | grep a*
(d) ls /bin | grep a$
(c) cut -f'' -d4
35. To find the number of commands that start with 'a'
(a) ls, grep, cut, count
(b) ls,
(d) ls,
(c) ls, grep, wc, cut
(e) none of the above
under /bin you need commands
grep, count, split
grep, wc, split](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5bad4e48-dad8-4710-a64b-b24b80d1efcf%2Fe3b7ff0a-79f1-4fed-977b-e289cd50cbf1%2Fkh0zplg_processed.png&w=3840&q=75)
Transcribed Image Text:31. Assuming ls -1 /home/cs288 returns a string
'drwxr-xr-x+ 1 CS288 CS288 123 Dec 25 2013'
the command to find the file size 123 is
(b)cut -d'' - £4
(e)none of the above
(a)cut -d'' -£3
(d)cut -f' ' -d4
32. Consider a list of file sizes 1st = (1 2 3 4 5), the average file size is computed by:
sum=0; n=${#1st [@] };
(a) for ((i=0;i<n;i++)); do ((sum-sum+1st[i])); done; ((avg=sum/n));
(b) for x in ${lst[@]}; do sum='expr $sum + $x'; done; avg='expr $sum / $n';
(c) for x in ${!lst[@]}; do ((sum-sum+lst[x])); done; ((avg=sum/n));
(d) all of the above
(e) none of the above
33. To list commands that start with
(a) ls /bin | grep ^a
(c) ls /bin | grep a
(e) none of the above
34. To list commands that end with 'a' under /bin you type
(b) ls /bin | grep a*
(d) ls /bin | grep as
(a) ls /bin | grep ^a
(c) ls /bin | grep a
(e) none of the above
'a' under /bin you type
(b) ls /bin | grep a*
(d) ls /bin | grep a$
(c) cut -f'' -d4
35. To find the number of commands that start with 'a'
(a) ls, grep, cut, count
(b) ls,
(d) ls,
(c) ls, grep, wc, cut
(e) none of the above
under /bin you need commands
grep, count, split
grep, wc, split
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