1. The leading coefficient of an odd-degree polynomial function A. As x→∞, y →∞ B. As x→∞, y → ∞ and as x→∞, y → -∞ and as x→∞, y → ∞ is positive. Which statement is true? C. As x→∞, y → ∞ and as x→∞o, y →∞ 2. Which polynomial function would have its end behaviour as x→ ±∞, y → ∞ A. f(x) = 17x² + 1 C. f(x) = -4x6 - 2x² + x³ - 7x² +9 D. As x→∞, y →∞ and as x→∞o, y →→∞ B. f(x) = -x³ + 5x² + 10x - 11 D. f(x) = 3x5-9x4+x³x²+2x-8 3. The degree of the polynomial function y = (−x + 4)¹ (2x − 1)² is A. 2 B. 4 C. 6 D. 8
1. The leading coefficient of an odd-degree polynomial function A. As x→∞, y →∞ B. As x→∞, y → ∞ and as x→∞, y → -∞ and as x→∞, y → ∞ is positive. Which statement is true? C. As x→∞, y → ∞ and as x→∞o, y →∞ 2. Which polynomial function would have its end behaviour as x→ ±∞, y → ∞ A. f(x) = 17x² + 1 C. f(x) = -4x6 - 2x² + x³ - 7x² +9 D. As x→∞, y →∞ and as x→∞o, y →→∞ B. f(x) = -x³ + 5x² + 10x - 11 D. f(x) = 3x5-9x4+x³x²+2x-8 3. The degree of the polynomial function y = (−x + 4)¹ (2x − 1)² is A. 2 B. 4 C. 6 D. 8
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:1. The leading coefficient of an odd-degree polynomial function is positive. Which statement is true?
A. As x→∞, y →→∞
and as x→ ∞, y →∞
C. As x→∞, y → ∞
and as x→∞, y →∞
B. As x→∞, y → ∞
and as x→∞, y →∞
2. Which polynomial function would have its end behaviour as x→ +∞, y → ∞
A. f(x) = 17x² + 1
C. f(x) = -4x6 − 2x² + x³ - 7x² +9
3. The degree of the polynomial function y = (−x + 4)ª(2x − 1)² is
A. 2
B. 4
C. 6
5. The function y =
A. x = -9
B. f(x) = -x³ + 5x² + 10x - 11
D. f(x) = 3x5 – 9x² + x³ − x² + 2x − 8
B. x = -2
4. Given a function f(x) with the function values ƒ(−6) = −24, ƒ(−2) = −20, ƒ(−1) = 0, and ƒ(4) = 64, which value of x
is a factor of the function?
A. x = -6
C. x = -1
: 4(−x + 9)¹ (2x − 3)²(x + 6) changes signs at
B. x = 9
D. As x→∞, y →∞
and as x→ ∞, y →∞
C. x =
2
D. 8
D. x = 4
D. x = -6
6. Which list best represents the values of x that make the following equation true: 3x³ + 6x² + 11x + 6 = 0 ?
A. ±1, ±2, ±3, ±6
B. +1, +2, +3,16,1,²
C. ±1,±2,±‚± ½ ‚± ²
D. 0,11,12,1 ²,² ± ± ²
![7. 6x4 - 2x³ - 21x² + 7x+8 is divided by 3x – 1 to give a quotient of 2x³ – 7x and a remainder of 8. Which statement
is true?
6x4-2x³-21x² +7x+8
A.
C. x = -
3
3x-1
= 2x³ - 7x +
8
3x-1
8. What is the solution to − (x − 3)(x + 8) < 0 ?
A. x € (-∞, -3) U (8, ∞)
B. x € (-∞, -8) U (3, 0)
B. 6x42x³ - 21x² + 7x + 8 = (3x − 1)(2x³ – 7x) − 8
D. All of these statements are true
C. x € (-∞, -8] U [3,00)
D. x € (-8,3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ef31c9f-1e44-437f-a71e-09574dc73129%2F2ceaa298-3c9b-445a-85de-bf28eb3a492a%2Fbbjx9jr_processed.png&w=3840&q=75)
Transcribed Image Text:7. 6x4 - 2x³ - 21x² + 7x+8 is divided by 3x – 1 to give a quotient of 2x³ – 7x and a remainder of 8. Which statement
is true?
6x4-2x³-21x² +7x+8
A.
C. x = -
3
3x-1
= 2x³ - 7x +
8
3x-1
8. What is the solution to − (x − 3)(x + 8) < 0 ?
A. x € (-∞, -3) U (8, ∞)
B. x € (-∞, -8) U (3, 0)
B. 6x42x³ - 21x² + 7x + 8 = (3x − 1)(2x³ – 7x) − 8
D. All of these statements are true
C. x € (-∞, -8] U [3,00)
D. x € (-8,3)
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