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1. The leading coefficient of an odd-degree polynomial function A. As x→∞, y →∞ B. As x→∞, y → ∞ and as x→∞, y → -∞ and as x→∞, y → ∞ is positive. Which statement is true? C. As x→∞, y → ∞ and as x→∞o, y →∞ 2. Which polynomial function would have its end behaviour as x→ ±∞, y → ∞ A. f(x) = 17x² + 1 C. f(x) = -4x6 - 2x² + x³ - 7x² +9 D. As x→∞, y →∞ and as x→∞o, y →→∞ B. f(x) = -x³ + 5x² + 10x - 11 D. f(x) = 3x5-9x4+x³x²+2x-8 3. The degree of the polynomial function y = (−x + 4)¹ (2x − 1)² is A. 2 B. 4 C. 6 D. 8

1. The leading coefficient of an odd-degree polynomial function A. As x→∞, y →∞ B. As x→∞, y → ∞ and as x→∞, y → -∞ and as x→∞, y → ∞ is positive. Which statement is true? C. As x→∞, y → ∞ and as x→∞o, y →∞ 2. Which polynomial function would have its end behaviour as x→ ±∞, y → ∞ A. f(x) = 17x² + 1 C. f(x) = -4x6 - 2x² + x³ - 7x² +9 D. As x→∞, y →∞ and as x→∞o, y →→∞ B. f(x) = -x³ + 5x² + 10x - 11 D. f(x) = 3x5-9x4+x³x²+2x-8 3. The degree of the polynomial function y = (−x + 4)¹ (2x − 1)² is A. 2 B. 4 C. 6 D. 8

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1. The leading coefficient of an odd-degree polynomial function is positive. Which statement is true? A. As x→∞, y →→∞ and as x→ ∞, y →∞ C. As x→∞, y → ∞ and as x→∞, y →∞ B. As x→∞, y → ∞ and as x→∞, y →∞ 2. Which polynomial function would have its end behaviour as x→ +∞, y → ∞ A. f(x) = 17x² + 1 C. f(x) = -4x6 − 2x² + x³ - 7x² +9 3. The degree of the polynomial function y = (−x + 4)ª(2x − 1)² is A. 2 B. 4 C. 6 5. The function y = A. x = -9 B. f(x) = -x³ + 5x² + 10x - 11 D. f(x) = 3x5 – 9x² + x³ − x² + 2x − 8 B. x = -2 4. Given a function f(x) with the function values ƒ(−6) = −24, ƒ(−2) = −20, ƒ(−1) = 0, and ƒ(4) = 64, which value of x is a factor of the function? A. x = -6 C. x = -1 : 4(−x + 9)¹ (2x − 3)²(x + 6) changes signs at B. x = 9 D. As x→∞, y →∞ and as x→ ∞, y →∞ C. x = 2 D. 8 D. x = 4 D. x = -6 6. Which list best represents the values of x that make the following equation true: 3x³ + 6x² + 11x + 6 = 0 ? A. ±1, ±2, ±3, ±6 B. +1, +2, +3,16,1,² C. ±1,±2,±‚± ½ ‚± ² D. 0,11,12,1 ²,² ± ± ²
Transcribed Image Text:1. The leading coefficient of an odd-degree polynomial function is positive. Which statement is true? A. As x→∞, y →→∞ and as x→ ∞, y →∞ C. As x→∞, y → ∞ and as x→∞, y →∞ B. As x→∞, y → ∞ and as x→∞, y →∞ 2. Which polynomial function would have its end behaviour as x→ +∞, y → ∞ A. f(x) = 17x² + 1 C. f(x) = -4x6 − 2x² + x³ - 7x² +9 3. The degree of the polynomial function y = (−x + 4)ª(2x − 1)² is A. 2 B. 4 C. 6 5. The function y = A. x = -9 B. f(x) = -x³ + 5x² + 10x - 11 D. f(x) = 3x5 – 9x² + x³ − x² + 2x − 8 B. x = -2 4. Given a function f(x) with the function values ƒ(−6) = −24, ƒ(−2) = −20, ƒ(−1) = 0, and ƒ(4) = 64, which value of x is a factor of the function? A. x = -6 C. x = -1 : 4(−x + 9)¹ (2x − 3)²(x + 6) changes signs at B. x = 9 D. As x→∞, y →∞ and as x→ ∞, y →∞ C. x = 2 D. 8 D. x = 4 D. x = -6 6. Which list best represents the values of x that make the following equation true: 3x³ + 6x² + 11x + 6 = 0 ? A. ±1, ±2, ±3, ±6 B. +1, +2, +3,16,1,² C. ±1,±2,±‚± ½ ‚± ² D. 0,11,12,1 ²,² ± ± ²
7. 6x4 - 2x³ - 21x² + 7x+8 is divided by 3x – 1 to give a quotient of 2x³ – 7x and a remainder of 8. Which statement is true? 6x4-2x³-21x² +7x+8 A. C. x = - 3 3x-1 = 2x³ - 7x + 8 3x-1 8. What is the solution to − (x − 3)(x + 8) < 0 ? A. x € (-∞, -3) U (8, ∞) B. x € (-∞, -8) U (3, 0) B. 6x42x³ - 21x² + 7x + 8 = (3x − 1)(2x³ – 7x) − 8 D. All of these statements are true C. x € (-∞, -8] U [3,00) D. x € (-8,3)
Transcribed Image Text:7. 6x4 - 2x³ - 21x² + 7x+8 is divided by 3x – 1 to give a quotient of 2x³ – 7x and a remainder of 8. Which statement is true? 6x4-2x³-21x² +7x+8 A. C. x = - 3 3x-1 = 2x³ - 7x + 8 3x-1 8. What is the solution to − (x − 3)(x + 8) < 0 ? A. x € (-∞, -3) U (8, ∞) B. x € (-∞, -8) U (3, 0) B. 6x42x³ - 21x² + 7x + 8 = (3x − 1)(2x³ – 7x) − 8 D. All of these statements are true C. x € (-∞, -8] U [3,00) D. x € (-8,3)
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