1. The freezing point depression of a solution of glucose (C,H1206, molar mass Calculate for the molarity of the glucose solution given that the density of the solution is 1.50 g/mL and the freezing point constant, Kf, of water is 1.86 °C kg mol·1. = 180.0 g/mol) is -10.3°C.

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Chapter1: Chemical Foundations
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please can u help me how to solve the number 1 question?

Colligative Properties in Ice Cream
Just a tip for the following questions, make sure you
know how to convert between molality and molarity and
vice versa.
1. The freezing point depression of a solution of glucose
(C,H1206, molar mass
Calculate for the molarity of the glucose solution
given that the density of the solution is 1.50 g/mL and
the freezing point constant, K¢, of water is 1.86 °C kg
mol-1.
180.0 g/mol) is -10.3°C.
2. Calculate for the final boiling point of a 2.70 M
aqueous solution of KBr. The boiling point constant of
water is 0.512 °C kg mol1, and the density of the KBr
solution is 1.80 g/mL.
Transcribed Image Text:Colligative Properties in Ice Cream Just a tip for the following questions, make sure you know how to convert between molality and molarity and vice versa. 1. The freezing point depression of a solution of glucose (C,H1206, molar mass Calculate for the molarity of the glucose solution given that the density of the solution is 1.50 g/mL and the freezing point constant, K¢, of water is 1.86 °C kg mol-1. 180.0 g/mol) is -10.3°C. 2. Calculate for the final boiling point of a 2.70 M aqueous solution of KBr. The boiling point constant of water is 0.512 °C kg mol1, and the density of the KBr solution is 1.80 g/mL.
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