1. The formation constant for the lead(II)-EDTA chelate, PbY2-, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0. %3D %3D
1. The formation constant for the lead(II)-EDTA chelate, PbY2-, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0. %3D %3D
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter21: The Chemistry Of The Main Group Elements
Section: Chapter Questions
Problem 97GQ
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Problem 2 requires a constant calculated in Problem 1, but I can't figure out Problem 1.
![1. The formation constant for the lead(II)-EDTA chelate, PbY2, is 1.10 x 1018. Calculate the
conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0.
%3D
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2d8e6b5-998c-4a7a-a44d-333492536780%2F15b88000-08a0-4701-98c7-6b3a45f78ed3%2Fk4tiz1h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. The formation constant for the lead(II)-EDTA chelate, PbY2, is 1.10 x 1018. Calculate the
conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0.
%3D
%3D
![2. Using the conditional formation constant calculated above, calculate -log[Pb] for 50.00 mL
of a solution of 0.0250 M Pb2*, at pH = 3.00, after the addition of: (a) 0.00 mL, (b) 50.0 mL, (c)
125 mL, and (d) 200. mL of 0.0100 M EDTA.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2d8e6b5-998c-4a7a-a44d-333492536780%2F15b88000-08a0-4701-98c7-6b3a45f78ed3%2Ficopq7r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Using the conditional formation constant calculated above, calculate -log[Pb] for 50.00 mL
of a solution of 0.0250 M Pb2*, at pH = 3.00, after the addition of: (a) 0.00 mL, (b) 50.0 mL, (c)
125 mL, and (d) 200. mL of 0.0100 M EDTA.
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