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1. The formation constant for the lead(II)-EDTA chelate, PbY2-, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0. %3D %3D

1. The formation constant for the lead(II)-EDTA chelate, PbY2-, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0. %3D %3D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Problem 2 requires a constant calculated in Problem 1, but I can't figure out Problem 1. 

1. The formation constant for the lead(II)-EDTA chelate, PbY2, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0. %3D %3D
Transcribed Image Text:1. The formation constant for the lead(II)-EDTA chelate, PbY2, is 1.10 x 1018. Calculate the conditional formation constant (K/) at: (a) pH = 3.00, and (b) pH = 10.0. %3D %3D
2. Using the conditional formation constant calculated above, calculate -log[Pb] for 50.00 mL of a solution of 0.0250 M Pb2*, at pH = 3.00, after the addition of: (a) 0.00 mL, (b) 50.0 mL, (c) 125 mL, and (d) 200. mL of 0.0100 M EDTA.
Transcribed Image Text:2. Using the conditional formation constant calculated above, calculate -log[Pb] for 50.00 mL of a solution of 0.0250 M Pb2*, at pH = 3.00, after the addition of: (a) 0.00 mL, (b) 50.0 mL, (c) 125 mL, and (d) 200. mL of 0.0100 M EDTA.
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