1. The following data give the number of analyses run byfour different operators during three different shifts. Isthere evidence that some of the operators perform moreproficiently during some shifts than others ? Using Chi-Square, find freedom degree , show the hypothesisNote that degree of confidence 98 % ,x tabulatedFrom table2%3DOperatorsShift1st2nd3rd4rdDay17151219Afternoon119.13102. The tabulated data represent tests run by three differentoperators on four different types of equipmentEstablish by analysis of variance whether there issignificant between operators & find freedom degree,show the hypothesis and the decision , Note thatdegree of confidence 95% , and F tabulated = 8.02EquipmentOperators1st2nd3rd4thA2018141216142014C1041412

Answered: 1. The following data give the number…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

1. The following data give the number of analyses run by
four different operators during three different shifts. Is
there evidence that some of the operators perform more
proficiently during some shifts than others ? Using Chi-
Square, find freedom degree , show the hypothesis
Note that degree of confidence 98 % ,x tabulated
From table
2
%3D
Operators
Shift
1st
2nd
3rd
4rd
Day
17
15
12
19
Afternoon
11
9.
13
10
2. The tabulated data represent tests run by three different
operators on four different types of equipment
Establish by analysis of variance whether there is
significant between operators & find freedom degree,
show the hypothesis and the decision , Note that
degree of confidence 95% , and F tabulated = 8.02
Equipment
Operators
1st
2nd
3rd
4th
A
20
18
14
12
16
14
20
14
C
10
4
14
12

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The main objective of an ANOVA (one-way) is to compare the means of more than two means to identify whether there is a statistically significant difference in the means. Additionally, for two-way ANOVA, three or more populations can be compared based on the means of two different factors. The null hypothesis in ANOVA is that all population mean are same. On the other hand, an alternate hypothesis is that at least one mean is different.