1. The Fe2+ content of iron tablets was determined by titration with a freshly standardised solution of potassium manganate(VII), KMN04. The equation for the titration reaction is 5Fe2+ + Mn04-+ 8H+ 5FE3+ + Mn2+ + 4H20 Maximum 5 iron tablets each is 0.065g of iron and 0.02 moldm potassium manganate (VII)(KMNO4) and 1 moldm aqueous sulfuric acid Describe how exactly 250 cm3 of Fe2+ solution was prepared from five iron tablets, each of mass 0.325 g in order to give a sensible titre. your calculations must be given

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1. The Fe2+ content of iron tablets was determined by titration with a freshly standardised
solution of potassium manganate(VII), KMNO4. The equation for the titration reaction is
5Fe2+ + Mn04-+8H+- 5FE3+ + Mn2+ + 4H2O
Maximum 5 iron tablets each is 0.065g of iron and 0.02 moldm potassium manganate
(VII)(KMNO4) and 1 moldm3 aqueous sulfuric acid
-3
Describe how exactly 250 cm3 of Fe2+ solution was prepared from five iron tablets, each of mass
0.325 g in order to give a sensible titre. your calculations must be given
Transcribed Image Text:1. The Fe2+ content of iron tablets was determined by titration with a freshly standardised solution of potassium manganate(VII), KMNO4. The equation for the titration reaction is 5Fe2+ + Mn04-+8H+- 5FE3+ + Mn2+ + 4H2O Maximum 5 iron tablets each is 0.065g of iron and 0.02 moldm potassium manganate (VII)(KMNO4) and 1 moldm3 aqueous sulfuric acid -3 Describe how exactly 250 cm3 of Fe2+ solution was prepared from five iron tablets, each of mass 0.325 g in order to give a sensible titre. your calculations must be given
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