1. The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft?). The article "Statistical Process Control of a Phosphate Coating Line" (Wire J. Intl., May 1997: 78-81) gave the accompanying data on tank temperature (x) and effi- ciency ratio (y). Temp. 170 172 173 174 174 175 176 Ratio .84 1.31 1.42 1.03 1.07 1.08 1.04 Temp. 177 180 180 180 180 180 181 Ratio 1.80 1.45 1.60 1.61 2.13 2.15 .84 Temp. 181 182 182 182 182 184 184 Ratio 1.43 90 1.81 1.94 2.68 1.49 2.52 Temp. 185 186 188 Ratio 13.00 1.87 3.08 a. Construct stem-and-leaf displays of both tempera- ture and efficiency ratio, and comment on interesting features. b. Is the value of efficiency ratio completely and unique- ly determined by tank temperature? Explain your reasoning.

1. The efficiency ratio for a steel specimen immersed in a phosphating tank is the weight of the phosphate coating divided by the metal loss (both in mg/ft?). The article "Statistical Process Control of a Phosphate Coating Line" (Wire J. Intl., May 1997: 78-81) gave the accompanying data on tank temperature (x) and effi- ciency ratio (y). Temp. 170 172 173 174 174 175 176 Ratio .84 1.31 1.42 1.03 1.07 1.08 1.04 Temp. 177 180 180 180 180 180 181 Ratio 1.80 1.45 1.60 1.61 2.13 2.15 .84 Temp. 181 182 182 182 182 184 184 Ratio 1.43 90 1.81 1.94 2.68 1.49 2.52 Temp. 185 186 188 Ratio 13.00 1.87 3.08 a. Construct stem-and-leaf displays of both tempera- ture and efficiency ratio, and comment on interesting features. b. Is the value of efficiency ratio completely and unique- ly determined by tank temperature? Explain your reasoning.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

"Using Regression create a semi Case Analysis using the data in the image below. There must be a hypothesis and conclusion." Please help I don't understand how to do this

1. The efficiency ratio for a steel specimen immersed in a
phosphating tank is the weight of the phosphate coating
divided by the metal loss (both in mg/ft?). The article
"Statistical Process Control of a Phosphate Coating
Line" (Wire J. Intl., May 1997: 78-81) gave the
accompanying data on tank temperature (x) and effi-
ciency ratio (y).
Temp. 170
172
173
174
174
175 176
Ratio
84
1.31
1.42
1.03
1.07
1.08 1.04
Temp. 177
180
180
180
180
180 181
Ratio
1.80
1.45
1.60
1.61
2.13
2.15 .84
Temp. 181
182
182
182
182
184 184
Ratio
1.43
90
1.81
1.94
2.68
1.49 2.52
Temp. 185
186
188
Ratio 13.00
1.87
3.08
a. Construct stem-and-leaf displays of both tempera-
ture and efficiency ratio, and comment on interesting
features.
b. Is the value of efficiency ratio completely and unique-
ly determined by tank temperature? Explain your
reasoning.
Construct a scatterplot of the data. Does it appear
that efficiency ratio could be very well predicted by
the value of temperature? Explain your reasoning.
c.

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