1. The demand equation for a product is p = 40 – 0.0004x, where p is the price per unit and x is the number of units sold. The total revenue for selling x units is Revenue = xp = x(40 – 0.0004x) How many units must be sold to produce a revenue of $100,000? (Round your answers to the nearest whole number.) x = ________ units (smaller value) x = ________ units (larger value) 2. Use the cost equation to find the number of units x that a manufacturer can produce for the given cost C. Round your answer to the nearest positive integer. C = 0.5x2 + 25x + 5000 C = $12,500 ________ units 3. Use the cost equation to find the number of units x that a manufacturer can produce for the given cost C. Round your answer to the nearest positive integer. C = 800 − 10x +x2 / 4 C = $1184 ________ units
Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
1. The demand equation for a product is p = 40 – 0.0004x, where p is the price per unit and x is the number of units sold. The total revenue for selling x units is
Revenue = xp = x(40 – 0.0004x)
How many units must be sold to produce a revenue of $100,000? (Round your answers to the nearest whole number.)
| x = ________ units (smaller value) |
| x = ________ units (larger value) |
2. Use the cost equation to find the number of units x that a manufacturer can produce for the given cost C. Round your answer to the nearest positive integer.
________ units
3. Use the cost equation to find the number of units x that a manufacturer can produce for the given cost C. Round your answer to the nearest positive integer.
________ units
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