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A small-business Web site contains 100 pages and 52%, 32%, and 16% of the pages contain low, moderate, and high graphic content, respectively. A sample of four pages is selected without replacement, and X and Y denote the number of pages with moderate and high graphics output in the sample. Determine the following:
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- A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…Twenty-nine college students, identified as having a positive attitude about Mitt Romney as compared to Barack Obama in the 2012 presidential election, were asked to rate how trustworthy the face of Mitt Romney appeared, as represented in their mental image of Mitt Romney’s face. Ratings were on a scale of 0 to 7, with 0 being “not at all trustworthy” and 7 being “extremely trustworthy.” Here are the 29 ratings: 2.6 3.2 3.7 3.3 3.4 3.6 3.7 3.8 3.9 4.1 4.2 4.9 5.7 4.2 3.9 3.2 4.5 5.0 5.0 4.6 4.6 3.9 3.9 5.3 2.8 2.6 3.0 3.3 3.7 a 95% confidence interval for the mean rating. Is there significant evidence at the 5% level that the mean rating is greater than 3.5 (a neutral rating)?
- In order to compare the real estate markets in Pittsburgh and Philadelphia, a realtor selected a random sample of 150 homes in the Pittsburgh area and 100 homes in the Philadelphia area. Shown below are dotplots showing the distribution of home price for the homes in these two cities.According to a recent census, 14.9%of all housing units in a certain country are vacant. A county supervisor wonders if her county is different from this. She randomly selects 832 housing units in her county and finds that 160 of the housing units are vacant. Complete parts a through d below. What is the P-value=???The Condé Nast Traveler Gold List provides ratings for the top 20 small cruise ships. The data shown below are the scores each ship received based upon the results from Condé Nast Traveler's Annual Readers' Choice Survey. Each score represents the percentage of respondents who rated a ship as excellent or very good on several criteria, including Shore Excursions and Food/Dining. An overall score was also reported and used to rank the ships. The highest ranked ship, the Seabourn Odyssey, has an overall score of 94.4, the highest component of which is 97.8 for Food/Dining. Shore Ship Overall Food/Dining Excursions Seabourn Odyssey 94.4 90.9 97.8 Seabourn Pride 93.0 84.2 96.7 National Geographic Endeavor 92.9 100.0 88.5 Seabourn Sojourn 91.3 94.8 97.1 Paul Gauguin 90.5 87.9 91.2 Seabourn Legend 90.3 82.1 98.8 Seabourn Spirit 90.2 86.3 92.0 Silver Explorer 89.9 92.6 88.9 Silver Spirit 89.4 85.9 90.8 Seven Seas Navigator 89.2 83.3 90.5 Silver Whisperer 89.2 82.0 88.6 National Geographic…
- At a football game, 40 fans were randomly surveyed. Of the sampled fans, 6 named Daren as the best player. Given this sample, if there are 12,000 fans altogether at the game, how many fans would likely name Daren as the best player? O 720 O 1,800 O 4,800 O 80,000 Choice Blocker Highlight Line Viewer Ruler Ruler (Grades 2&3) Protractor Calc Basic Calc Sci Reference Try Desmos Graphing CalcAn industrial-organizational psychologist is interested in discovering the relationship between the tempo of preferred music that is played in a workplace and employee mood. Employees chose their favorite song on an MP3 player and then reported their moods when listening to that piece of music. A total of 10 participants were asked individually and brought in their own MP3 players; the least number of songs on an employee's MP3 player was 350. The sample data are presented as a scatterplot below. The psychologist wants to use a Pearson correlation coefficient to analyze the relationship. Considering the assumptions for this statistic, which of these statements is the correct course of action? A. The researcher has chosen the wrong statistic to represent this relationship. B. The researcher has violated a robust assumption and should be able to calculate r. C. The researcher has chosen the right statistic because all the assumptions are valid. D. The researcher has violated a…A random sample of 40 students from each grade level was surveyed regarding their preference for a class field trip. If there are 180 members of the 8th grade class, then what percent preferred either the museum or the sports complex? Show your work.
- A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 56 people she sampled who work out in the morning have a mean of 4.4 hours of exercise each week. The 63 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.7 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2: Construct a 99% confidence interval for the true difference between the mean amounts of…The owner of Showtime Movie Theaters, Inc., would like to predict weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow. Weekly Television Newspaper Gross Revenue Advertising Advertising ($1,000s) ($1,000s) ($1,000s) 97 5.0 1.5 2.0 2.0 06 95 4.0 1.5 92 2.5 2.5 103 3.0 3.3 94 3.5 2.3 94 2.5 4.2 105 3.0 2.5 a. Develop an estimated regression equation with the amount of television advertising as the independent variable (to 1 decimal). Revenue = TVAdv b. Develop an estimated regression equation with both television advertising and newspaper advertising as the independent variables (to 2 decimals). Revenue = TVAdv + NVAdv c. Is the estimated regression equation coefficient for television advertising expenditures the same in part (a) and in part (b)? - Select your answer - Interpret the coefficient in each case. In - Select your answer - :, the coefficient is an estimate of the change in revenue due to a one-unit change in…