1. The average wait time for tickets at a certain movie theatre is 10 minutes. The average wait time for popcorn is 5 minutes. Find the probability that the total wait time is under 20 minutes. Assume the line for tickets is independent of the line for popcorn. (Answer is about 75%)

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Explain how the answer is equal to 75%
**Problem 1: Probability in Movie Theater Lines**

The average wait time for tickets at a certain movie theatre is 10 minutes. The average wait time for popcorn is 5 minutes. Find the probability that the total wait time is under 20 minutes. Assume the line for tickets is independent of the line for popcorn. (Answer is about 75%)

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**Explanation:**

This problem involves understanding the probability of combined wait times being less than a specified total. The wait times are independent, meaning the total wait time is the sum of two independent random variables. The solution requires calculating the probability that the combined wait time from both activities falls under the total limit of 20 minutes, using given averages and assumptions.
Transcribed Image Text:**Problem 1: Probability in Movie Theater Lines** The average wait time for tickets at a certain movie theatre is 10 minutes. The average wait time for popcorn is 5 minutes. Find the probability that the total wait time is under 20 minutes. Assume the line for tickets is independent of the line for popcorn. (Answer is about 75%) --- **Explanation:** This problem involves understanding the probability of combined wait times being less than a specified total. The wait times are independent, meaning the total wait time is the sum of two independent random variables. The solution requires calculating the probability that the combined wait time from both activities falls under the total limit of 20 minutes, using given averages and assumptions.
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