1. The 4-kN force F is applied at point A Compute the moment of F atoul point O expressing it both as a scalar and as a vector quantity Detemine the coordinates of the points on the x and y-axes about which the moment of F is zero Ans 2.00 kN.m. (13.0) (0.0 78)

Status F(N) X1 (m) 0.8 X2 (m) Y1 (m) 2.4 21 (m) 1.8 400 1.7 oaded system below, determine the moment about point C and the moment about line OC. Select the dosest choice to your solution and ONLY TYPE THE LETTER IN THE BLANK ((A B.CD. E Y1 The force FAB(in N) in cartesian vector form A FAB-457+ Oj- 483k B. FAR- 1821 + oj - 192k C. FAB-O- 291)- 291k D. FAB- 2751 + Oj - 291k E. FAR-1821 -291) - 192k X1 Answer for (Q1 Z1 The moment about point C (in N.m): A Mc-698I- 233- 660k 8. MC 461i-660 - 436k C. MC-2331 - 660 - 660k D. MC--11591 - 387) - 1096k E. MC4611-154 - 436k F. Answer for (Q2): X2 The moment about line OCC A. -776 N.m B. -1285.9 N.m C. -886.8 N.m D. -1019.8 N.m E. 1197.2 N.m Answer for (Q3): X1 (m) 0.8 X2 (m) 1.7 Y1 (m) 2.4 21 (m) 1.8 (N) ec : bsest choice to your solution and ONLY TYPE THE LETTER IN THE BLANK (A B.CD. E). :01 l 4G

600 N 2) Determine the resultant R of the two forces shown by (a) applying the parallelogram rule for vector addition and (b) summing scalar components. 400 N 60 Ans. (a) R= 529 N (b) R= - 100 + 520 j N

Q.5) Three forces are applied to bracket as shown in figure below. Replace the given force system by a resultant force system acting at point O. Then replace the resultant force system by the simplest resultant and locate its line of action as it passes through the y-z plane. y 800 N -ve z 70 mm 40 mm C 40 mm 120 mm Z 245° - X 1000 N 600N 60° D E(150 mm, -50 mm, 100 mm) 110 mm B/ y 1 45° 30° X