PYTHON PROGRAMMING (practice review for final) (please see attached) ### Validating an ID Card NumberThe process of validating an ID card number involves the following steps:1. **Double the Digits:** - Starting with the leftmost digit, double it. - Then, double every other digit after it. - If any doubled digit is a two-digit number, subtract 9 from it. - Sum these new digits. - **Example:** For the ID card number 5866793610024475, the digits to be doubled are 5, 6, 7, 3, 1, 0, 4, 7. The replacements after adjusting doubles are: - 5 → 5*2 = 10 → 10-9 = 1 - 6 → 6*2 = 12 → 12-9 = 3 - 7 → 7*2 = 14 → 14-9 = 5 - 3 → 3*2 = 6 - 1 → 1*2 = 2 - 0 → 0*2 = 0 - 4 → 4*2 = 8 - 7 → 7*2 = 14 → 14-9 = 5 - The sum of these numbers: 1 + 3 + 5 + 6 + 2 + 0 + 8 + 5 = 30.2. **Sum the Remaining Digits:** - Sum the digits in the odd-numbered positions. - **Example:** Using the above ID card number, this results in 8 + 6 + 9 + 6 + 0 + 2 + 4 + 5 = 40.3. **Validate the Sum:** - Add the two sums together. If the result is a multiple of 10, the ID card number is valid. - In our example: 30 + 40 = 70, and 70 is a multiple of 10, so the ID card is valid.### Graph Explanation- A table is provided to illustrate the doubling process and adjustments for values from 0-15, showing both the original and modified values.### Program OutputThe program examples demonstrate how to check and validate ID card numbers:- **Valid Case:** - Input: 586679361

code is given below import java.util.Scanner; public class Main { // Main Method public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("enter the ID card number : "); long number = input.nextLong(); System.out.println(number + " is " + (isValid(number) ? "valid" : "is not valid")); } public static boolean isValid(long number) { return ((sumOfDoubleEvenPlace(number) + sumOfOddPlace(number)) % 10 == 0); } // Get the result from Step 2 public static int sumOfDoubleEvenPlace(long number) { int sum = 0; String num = number + ""; for (int i = getSize(number) - 2; i >= 0; i -= 2) sum += getDigit(Integer.parseInt(num.charAt(i) + "") * 2); return sum; } // Return this number if it is a single digit, otherwise, // return the sum of the two digits public static int getDigit(int number) { if (number < 16) return number; return number / 10 + number % 10; } // Return sum of odd-place digits in number public static int sumOfOddPlace(long number) { int sum = 0; String num = number + ""; for (int i = getSize(number) - 1; i >= 0; i -= 2) sum += Integer.parseInt(num.charAt(i) + ""); return sum; } public static boolean prefixMatched(long number, int d) { return getPrefix(number, getSize(d)) == d; } public static int getSize(long d) { String num = d + ""; return num.length(); } public static long getPrefix(long number, int k) { if (getSize(number) > k) { String num = number + ""; return Long.parseLong(num.substring(0, k)); } return number; } }