1. Solve the recurrence relation subject to the basis step (i). P(1)=2 (ii). P(n) = 2P(n − 1) + n2n for n ≥ 2 2. Solve the recurrence relation subject to the initial conditions (i). P(1)=5 (ii). P(2)=17 (iii). P(n) = 7P(n − 1) – 12P(n – 2) for n ≥ 3
1. Solve the recurrence relation subject to the basis step (i). P(1)=2 (ii). P(n) = 2P(n − 1) + n2n for n ≥ 2 2. Solve the recurrence relation subject to the initial conditions (i). P(1)=5 (ii). P(2)=17 (iii). P(n) = 7P(n − 1) – 12P(n – 2) for n ≥ 3
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
Transcribed Image Text:1. Solve the recurrence relation subject to the basis step
(i). P(1)=2
(ii). P(n) = 2P(n − 1) + n2n for n ≥ 2
2. Solve the recurrence relation subject to the initial conditions
(i). P(1)=5
(ii). P(2)=17
(iii). P(n) = 7P(n − 1) – 12P(n – 2) for n ≥ 3
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