1. Solve the following queries (parts a), b), & c)) dealing with volumetric analysis. Make sure you show complete procedures a) A solid mixture weighing 0.05485 g contained only ferrous ammonium sulfate and ferrous chloride. The sample was dissolved in 1 M H₂SO4, and the Fe²+ required 13.39 mL of 0.012 34 M Ce4+ for complete oxidation to Fe³+ (Ce4+ + Fe²+ → Ce³+ + Fe³+). Calculate the weight percent of Cl in the original sample. FeSO4 (NH4)2SO4.6H₂O Ferrous ammonium sulfate FM 392.13 FeCl₂ 6H₂O Ferrous chloride FM 234.84
1. Solve the following queries (parts a), b), & c)) dealing with volumetric analysis. Make sure you show complete procedures a) A solid mixture weighing 0.05485 g contained only ferrous ammonium sulfate and ferrous chloride. The sample was dissolved in 1 M H₂SO4, and the Fe²+ required 13.39 mL of 0.012 34 M Ce4+ for complete oxidation to Fe³+ (Ce4+ + Fe²+ → Ce³+ + Fe³+). Calculate the weight percent of Cl in the original sample. FeSO4 (NH4)2SO4.6H₂O Ferrous ammonium sulfate FM 392.13 FeCl₂ 6H₂O Ferrous chloride FM 234.84
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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show full and complete procedure. please answer parts a), b) & c). Note they are subparts of the same question

Transcribed Image Text:1. Solve the following queries (parts a), b), & c)) dealing with volumetric analysis. Make sure you show complete
procedures
a)
A solid mixture weighing 0.05485 g contained only ferrous ammonium sulfate
and ferrous chloride. The sample was dissolved in 1 M H₂SO4, and the Fe²+
required 13.39 mL of 0.012 34 M Ce4+ for complete oxidation to Fe³+ (Ce4+ + Fe²+
→ Ce³+ + Fe³+). Calculate the weight percent of Cl in the original sample.
2+
FeSO4 (NH4)2SO4 · 6H₂O
.
Ferrous ammonium sulfate
FM 392.13
FeCl2 6H₂O
Ferrous chloride
FM 234.84
b)
A 50.0-mL solution containing Ni²+ and n²+ was treated with 25.0 mL of 0.0452
M EDTA to bind all the metal. The excess unreacted EDTA required 12.4 mL of
0.012 3 M Mg2+ for complete reaction. An excess of the reagent 2,3-dimercapto-
1-propanol was then added to displace the EDTA from zinc. Another 29.2 mL of
Mg2+ were required for reaction with the liberated EDTA. Calculate the molarity
of Ni²+ and Zn²+ in the original solution.
How many millimoles of solute are contained in:
(a) 2.95 mL of 0.0789 M KH₂PO4?
(b) 0.2011 L of 0.0564 M HgCl₂?
(c) 2.56 L of a 47.5 ppm solution of Mg(NO3)2?
(d) 79.8 mL of 0.1379 M NH4VO3?
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