1. Solve the following LP problem using the simplex method.Minimizesubject toC=1800z+2000y + 3200:4x + 2y + 4z 26r+2y + 2z28z+y+z2520,20,2 20

The objective is to: Minimize: C = 1800x + 2000y + 3200z Subject to the constraints, 4x + 2y + 4z ≥…

Answered: 1. Solve the following LP problem using…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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1. Use the simplex method in tabular form to solve the problem: Maximize Z= 2x1 + 4x2 + 3x3 subject to and 21 +372 +2r3 ≤ 30 21+22+13 ≤ 24 3x1 +52 + 3x3 ≤60 2120, 220, 23 20.
3.) Solve applying the simplex method to the dual problem. Minimize C= 6y, +8y, +12y, Subject to y, +3y, +3y, 2 6 Y +5y, +5y, 2 4 2y, +2y, +3y, 28 Y1, Y2, y3 20
subject to x1 = x₂ = Z Use the simplex method to maximize z = 6x₁ + 11x2 3x₁ x 1 x1 X2 + X2 0 > 0
Work through the simplex method (in algebraic form) step by step to solve the following problem. Maximize Z = x1 + 2x2 + 2x3, subject to 5x1 + 2x2 + 3x3 ≤ 15 x1 + 4x2 + 2x3 ≤ 12 2x1+ x3 ≤ 8 and x1 ≥ 0, x2 ≥ 0, x3 ≥ 0.
Use the simplex method to solve the following simplex problems. a) Maximise 6x1 + 9x2 + 6x3 subject to 3x1 + 2x2 + x3 = 0.
Use the simplex method to solve the following. Maximize z = 4x1 + 4x2 - 8x3 subject to 5x1 + 5x2 - 10хз 5 95 6х1 + 6x2 + 12х35 128 X120, х2 2 0, Хз 20. ..... Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. Treating x2 as a nonbasic variable, the maximum is when x1 = X2 = X3 , s, = 0 and s2 = %3D B. There is no maximum solution for this problem.
Minimize subject to C = 13x₁ + 2x2 4x₁ + x₂ ≥ 25 3x1 + x₂ 26 X1, X2 20 C a. Form the dual problem. Maximize P = 25 y₁ +6y₂ subject to 4 y₁ + 3y₂ ≤ 13 Y₁ + 1 y2 ≤ 2 y₁, y₂ 20 b. Find the solution to the original problem by applying the simplex method to the dual problem. Select the correct choice below and fill in any answer boxes within your choice. O Min C = at x₁ and x₂ = O The optimal solution does not exist.
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What are the values for the pivot column in the second simplex table for the following equation: Minimize Z= 10X1 + 15X2 + 8X3; Subject to: 5X1+ 2X2 + X3 = 3 a. 1/ 0.25 / 1.57 b. 4.14 / 1.85 / 0.28 c. 0.14/ -0.57 / 0.14 d. 4.14 / -2.42 | 0.85 e. 1.71 / 1.85 / 0.28

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1. Solve the following LP problem using the simplex method. Minimize subject to 4r + 2y + 4z 26 1+2y+2:28 z+y+z25 C=1800r +2000y + 3200z z20, y ≥ 0, z 20