1. Solve the differential equation, The boundary conditions are y(0) = 0; dx d²y dx² +1²y = 0 (1) = 0. Note that y = 0 is a trivial solution of the problem. Find the first two values of 2.

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Aa.26.

 

1. Solve the differential equation,
The boundary conditions are y(0) = 0;
dx
d²y
dx²
The boundary conditions are y(0) = 0;
+1²y = 0
(1) = 0.
Note that y = 0 is a trivial solution of the problem. Find the first two values of 2.
2. Solve the differential equation
d²y dy
dx² dx
-
+2²y = 0
dy (1) = 0.
dx
Hint: Transform the problem using y(x) = W (x)ez. Find the first two values of 2.
Transcribed Image Text:1. Solve the differential equation, The boundary conditions are y(0) = 0; dx d²y dx² The boundary conditions are y(0) = 0; +1²y = 0 (1) = 0. Note that y = 0 is a trivial solution of the problem. Find the first two values of 2. 2. Solve the differential equation d²y dy dx² dx - +2²y = 0 dy (1) = 0. dx Hint: Transform the problem using y(x) = W (x)ez. Find the first two values of 2.
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