1. sin x csc x 5. cos x (tan x + 1)

Q: 3 secx xp. 2+3 tan x

A: Solve the following

Q: secx-tan x cos x %3D 1+sin x secx+tanx

A: consider the left hand side of the equation sec x -tan xsec x +tan x sec x -tan xsec x +tan x=1cos x…

Q: Differentiate sin x +1

A:

Q: if Sec X = 2 then tanx +Cos X =

A:

Q: (sin 8) (csc³ 0-csc²0- sec 0 tano) de 6)

A:

Q: Cos(10+x)

A: Here , We will apply the formula of Cos ( A+B) Cos(A+B) = [CosA CosB - SinA SinB ]

Q: 1 + csc x  / cos x + cot x

A: Given information:

Q: tan(x²) D, secx

A:

Q: Simplify the expression. tan(sin 'x) a. . sin(tan-'x) a.

A: use pythagorean theorem and right angle triangle.

Q: Evaluate sec x dx VIn(sec x + tan x)

A: We will let,  ln( sec x+tan x) = t  to solve this question.