1. S x²+x+3 (x-2)(x+1) dx

Q: dx 8x In(x) - 7x

A: I=∫dx8xln⁡(x)−7x

Q: Vx-x (-X dx 4. x3

A:

Q: Differentiate. y= In [(x + 4)(5x– 6)(3 – x)] d dy In ((x+ 4)(5x – 6)(3–x))) = |

A: Given: To find: The derivative of the given function.

Q: (x² (а3 — 2)da 4x +

A:

Q: 9. (x – 14) dx 2

A: Fundamental theorem of calculus allows us to reduce computing the definite integral to computing a…

Q: 2. S (x * - x³ -3x) dx V4

A: Explanation of the answer is as follows

Q: S(x4 – 4x5

A: Evaluate the integral

Q: Vx - 2 dx 5 x*(Vĩ + 1)

A: I have stated the used formulas in the solution

Q: d/dx [(2x+1)3(3x2-1)4]

A:

Q: 3. (1+4e3x)³ e3x dx

A:

Q: 2 S(4x3 + )dx x+1

A:

Q: S dx 2 (1+x²)²

A:

Q: (2x + 1)1º x² dx

A:

Q: Find √√3 x² +3 x² +1 dx

A:

Q: S 3x-7 (5-12x-9x²)² 3/2 dx

A: ∫3x-75-12x-9x23/2dx

Q: dx 4+x*

A: Proceed as shown below...

Q: x(x²-x+2) dx is equal to 3

A:

Q: Find y". y = x(3x + 1)* y" =L

A: Given function is  y= x(3x+1)4  We have to find : y".

Q: 5x dx (x² + 3)2/3

A: We will use a substitution to solve the equation.

Q: S(3x* – 5xP +x=³)dx.

A: Given query is to find the integral.

Q: S(2-x) In(4x)dx

A:

Q: (x²+1)dx 10. x2

A:

Q: dx 0 (3+x)² 2 동

A:

Q: ム× dx (x2+1) (3x-2)

A:

Q: 1 = f(y-x(2-x))dx 21

A: Given: I=∫02δy-x2-x dxTo find: The value of the given integral.

Q: 312 dx x + 1

A: We have to find the value of ∫x3/2x+1dx

Q: √(x + 3) dx √16-x²

A: Solution

Q: (x3-4) 2. S dx x3+2x2+2x

A: To evalaute: I=∫x3-4x3+2x2+2xdx=∫1-2x2+2x+4x3+2x2+2xdx=∫dx-∫2x2+2x+4x3+2x2+2xdx

Q: S (3x² + 8x) / (x³ + 4x² - 5)dx %3D

A: The given integral is ∫3x2+8xx3+4x2-5dx