1. (Proximal Gradient Descent) In this problem, we will show the sublinear convergence for proximal gradient descent. To be precise, we assume that the objective f(x) can be written as f(x) = g(x) + h(x), where (a) g is convex, differentiable, and dom(g) € Rd. (b) Vg is Lipschitz, with constant L > 0. (c) h is convex, not necessarily differentiable, and we take dom(h) = Rd for simplicity. By defining the generalized gradient to be: G(x) = L(xk – X+1), where xk+1 is next iterate obtained from applying PGD to xk. Show that f(xk+1) - f(x*) ≤ ( |x − x*||² — ||×xk+1 − x*||²), where x* is the minimizer of f, and use it to conclude L f(xk) - f(x*) ≤ xo-x*||². 2k That is, the proximal descent method achieves O(1/k) accuracy at the k-th iteration. Hint: You can freely use the following lemma, which shows that the PGD is also a "descent method": Lemma 1 (Proximal Descent Lemma). 1 f(xk+1) − f(z) ≤ G(xk)¯(xk — z) - - ||G(x)||2, VzЄR". 2L
1. (Proximal Gradient Descent) In this problem, we will show the sublinear convergence for proximal gradient descent. To be precise, we assume that the objective f(x) can be written as f(x) = g(x) + h(x), where (a) g is convex, differentiable, and dom(g) € Rd. (b) Vg is Lipschitz, with constant L > 0. (c) h is convex, not necessarily differentiable, and we take dom(h) = Rd for simplicity. By defining the generalized gradient to be: G(x) = L(xk – X+1), where xk+1 is next iterate obtained from applying PGD to xk. Show that f(xk+1) - f(x*) ≤ ( |x − x*||² — ||×xk+1 − x*||²), where x* is the minimizer of f, and use it to conclude L f(xk) - f(x*) ≤ xo-x*||². 2k That is, the proximal descent method achieves O(1/k) accuracy at the k-th iteration. Hint: You can freely use the following lemma, which shows that the PGD is also a "descent method": Lemma 1 (Proximal Descent Lemma). 1 f(xk+1) − f(z) ≤ G(xk)¯(xk — z) - - ||G(x)||2, VzЄR". 2L
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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