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1. Prove whether 8 1 Σ(-1)+1. j2/3 j=1 converges absolutely, converges conditionally, or diverges.

1. Prove whether 8 1 Σ(-1)+1. j2/3 j=1 converges absolutely, converges conditionally, or diverges.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Real Analysis II: Solve the problem in photo 1 following notes in photo 2
1. Prove whether 8 Σ(-1)+1_1 j2/3 j=1 converges absolutely, converges conditionally, or diverges.
Transcribed Image Text:1. Prove whether 8 Σ(-1)+1_1 j2/3 j=1 converges absolutely, converges conditionally, or diverges.
{a} 09. AST. I fant in numbers and Defi Eaj ex. 2.0 Conv. by A-S-T ex. |a₁ ≤ ( 8 W. &a fact a lim an o is abs Conv. abs. Conv.. because J+1 Study 3/5 = 1/2 1/² "1 is E B₁Aj every Eaj decreasing seg of positive then & (-1)+ NOT Thim: (Absolute Convergence Test) If Assume If Eaj Conv. abs, then 2(a) Conv. Eaj Conv. abs. [Since |aj| = |aj| t; = 1, ... j we Ɛaj get Eaj Conv. 80 if 2 lail Conv... yes abs. Conv. an Converges- Conv. (P-Sehes p=2 X EA CON. (Harmonic, Siv) Problem Bj Elajh Conv. aux Coution the Converse is false Def if Eaj Conv. but does not Conv. abs then Eag Convergo Condition 22 either diverges Conv. abs, от Conv. Conditi EGI A = 1 = 1/2 + 1/3 - 1/14 + 1/5 - 1/6 + 1/ 7- / 8 + 1/ 7- / 10 + 1/11 - 1/12 + 1/3 - 1/12/ #½-1⁄2-1⁄4-16-18-1/10 - 1/12 - 1/14
Transcribed Image Text:{a} 09. AST. I fant in numbers and Defi Eaj ex. 2.0 Conv. by A-S-T ex. |a₁ ≤ ( 8 W. &a fact a lim an o is abs Conv. abs. Conv.. because J+1 Study 3/5 = 1/2 1/² "1 is E B₁Aj every Eaj decreasing seg of positive then & (-1)+ NOT Thim: (Absolute Convergence Test) If Assume If Eaj Conv. abs, then 2(a) Conv. Eaj Conv. abs. [Since |aj| = |aj| t; = 1, ... j we Ɛaj get Eaj Conv. 80 if 2 lail Conv... yes abs. Conv. an Converges- Conv. (P-Sehes p=2 X EA CON. (Harmonic, Siv) Problem Bj Elajh Conv. aux Coution the Converse is false Def if Eaj Conv. but does not Conv. abs then Eag Convergo Condition 22 either diverges Conv. abs, от Conv. Conditi EGI A = 1 = 1/2 + 1/3 - 1/14 + 1/5 - 1/6 + 1/ 7- / 8 + 1/ 7- / 10 + 1/11 - 1/12 + 1/3 - 1/12/ #½-1⁄2-1⁄4-16-18-1/10 - 1/12 - 1/14
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