1. Problem Description: The total nuclear binding energy is the energy required to split a nucleus of an atom in its component parts: protons and neutrons, or, collectively, the nucleons. It describes how strongly nucleons are bound to each other. When a high amount of energy is needed to separate the nucleons, it means nucleus is very stable and the neutrons and protons are tightly bound to each other. The atomic number or proton number (symbol Z) is the number of protons found in the nucleus of an atom. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom. + Binding energy Nucleus (smaller mass) Separated nucleons (greater mass) Figure 1: Binding Energy in the Nucleus The approximate nuclear binding energy Eb in million electron volts, of an atomic nucleus with atomic number Z and mass number A is calculated using the following formula: (A – 22)² as Eb = a,A – A2A³ – az¬- as A A3 AZ where, a, = 15.67, az = 17.23, az = 0.75, a, = 93.2 ,and if A is odd if A and Z are both even if A is even and Z is Odd 12.0 as= -12.0 The binding energy per nucleon (BEN) is calculated by dividing the binding energy (Eb) by the mass number (A) You are asked to write a program that requests the user for a valid atomic number (Z) then goes through all values of A from A = Z to A = 4Z. For example, if the user inputs 5 for Z then A will be all numbers from 5 (Z) to 20 (4 Z) inclusive, see the example output in figure 2. If the user enters invalid atomic number that is not between 1 and 118, the program should give the user another chance to enter a valid input as shown in figure 2. Your main task is to find the nucleus with the highest binding energy per nudleon, which corresponds to the most stable configuration (figure 2), and writes a copy of the table to a text file named output.bt (figure3). In 125): runfilel'users/hanzazidoun/Documents/2101/2101_S2021/ Progranning Assignnents/PA4/pa4_nuc lear.py', wdire'/users/hamzazidoun/ Docunents/2101/zies_sze21/Programing Assignnents/PA4) Enter valid atonic nunber (2) (1,118): e Enter valid atonic number (z) (1,118): -120 Enter valid atonic nunber (2) (1,118): 200 Enter valid atonic nunber (z) (1,118]: 5 binding energy binding, energy per Nuc leon 15 -448.996 -226.623 -89.799 -82.990 -3.778 47.111 64.228 70.245 55.009 35.952 1.794 -32.682 -78.825 -123.453 -177.641 -229.307 -289.143 -37.771 -11.856 4.472 5.235 6.423 6.386 4.584 2.766 0.128 11 12 13 14 15 16 -2.179 -4.927 -7.262 -9.869 -12.069 -14.457 17 18 19 The most stable nucleus has a mass number 10

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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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1. Problem Description:
The total nuclear binding energy is the energy required to split a nucleus of an
atom in its component parts: protons and neutrons, or, collectively, the nucleons.
It describes how strongly nucleons are bound to each other. When a high amount
of energy is needed to separate the nucleons, it means nucleus is very stable
and the neutrons and protons are tightly bound to each other.
The atomic number or proton number (symbol Z) is the number of protons found
in the nucleus of an atom. The sum of the atomic number Z and the number of
neutrons N gives the mass number A of an atom.
+ Binding energy -
Nucleus
(smaller mass)
Separated nucleons
(greater mass)
Figure 1: Binding Energy in the Nucleus
The approximate nuclear binding energy Eb in million electron volts, of an atomic
nucleus with atomic number Z and mass number A is calculated using the
following formula:
(A – 22)², as
Eb = a,A – 4,A³ – az¬- as-
Eb = a, A - a½A3 – az
A
A3
AZ
where, a, = 15.67, az = 17.23, az = 0.75, a, = 93.2 ,and
if A is odd
if A and Z are both even
if A is even and Z is Odd
12.0
as =
(-12.0
The binding energy per nucleon (BEN) is calculated by dividing the binding
energy (Eb) by the mass number (A).
You are asked to write a program that requests the user for a valid atomic
number (Z) then goes through all values of A from A = Z to A = 4Z. For example,
if the user inputs 5 for Z then A will be all numbers from 5 (Z) to 20 (4 Z)
inclusive, see the example output in figure 2.
If the user enters invalid atomic number that is not between 1 and 118, the
program should give the user another chance to enter a valid input as shown in
figure 2.
Your main task is to find the nucleus with the highest binding energy per nucleon,
which corresponds to the most stable configuration (figure 2), and writes a copy
of the table to a text file named output.txt (figure3).
In (25]: runfilel'/Users/hanzazidoun/Documents/2101/2101_52021/
Progranning Assignnents/PA4/pa4_nuc lear.py, wdire' /Users/hamzazidoun/
Documents/2101/2ie1_s2e21/Progranning Assignments/PA4)
>>>Enter valid atomic number (Z) (1,118]: e
>Enter valid atonic number (z) (1,118]: -120
>>Enter valid atomic number (2) (1,118]: 200
>>Enter valid atomic number (2) (1,118): 5
A
binding
energy
binding energy
per Nucleon
-448.996
ww...
-89.799
-37.771
-11.856
-0.472
5.235
6.423
6.386
-226.623
-82.990
-3.778
8
47.111
64.228
70.245
55.009
35.952
1.794
-32.682
-78.825
-123.453
-177.641
-229.307
-289.143
11
12
12
4.584
2.766
14
15
16
17
18
19
20
0.128
-2.179
-4.927
-7.262
-9.869
-12.069
-14.457
The most stable nucleus has a mass number 10
Transcribed Image Text:1. Problem Description: The total nuclear binding energy is the energy required to split a nucleus of an atom in its component parts: protons and neutrons, or, collectively, the nucleons. It describes how strongly nucleons are bound to each other. When a high amount of energy is needed to separate the nucleons, it means nucleus is very stable and the neutrons and protons are tightly bound to each other. The atomic number or proton number (symbol Z) is the number of protons found in the nucleus of an atom. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom. + Binding energy - Nucleus (smaller mass) Separated nucleons (greater mass) Figure 1: Binding Energy in the Nucleus The approximate nuclear binding energy Eb in million electron volts, of an atomic nucleus with atomic number Z and mass number A is calculated using the following formula: (A – 22)², as Eb = a,A – 4,A³ – az¬- as- Eb = a, A - a½A3 – az A A3 AZ where, a, = 15.67, az = 17.23, az = 0.75, a, = 93.2 ,and if A is odd if A and Z are both even if A is even and Z is Odd 12.0 as = (-12.0 The binding energy per nucleon (BEN) is calculated by dividing the binding energy (Eb) by the mass number (A). You are asked to write a program that requests the user for a valid atomic number (Z) then goes through all values of A from A = Z to A = 4Z. For example, if the user inputs 5 for Z then A will be all numbers from 5 (Z) to 20 (4 Z) inclusive, see the example output in figure 2. If the user enters invalid atomic number that is not between 1 and 118, the program should give the user another chance to enter a valid input as shown in figure 2. Your main task is to find the nucleus with the highest binding energy per nucleon, which corresponds to the most stable configuration (figure 2), and writes a copy of the table to a text file named output.txt (figure3). In (25]: runfilel'/Users/hanzazidoun/Documents/2101/2101_52021/ Progranning Assignnents/PA4/pa4_nuc lear.py, wdire' /Users/hamzazidoun/ Documents/2101/2ie1_s2e21/Progranning Assignments/PA4) >>>Enter valid atomic number (Z) (1,118]: e >Enter valid atonic number (z) (1,118]: -120 >>Enter valid atomic number (2) (1,118]: 200 >>Enter valid atomic number (2) (1,118): 5 A binding energy binding energy per Nucleon -448.996 ww... -89.799 -37.771 -11.856 -0.472 5.235 6.423 6.386 -226.623 -82.990 -3.778 8 47.111 64.228 70.245 55.009 35.952 1.794 -32.682 -78.825 -123.453 -177.641 -229.307 -289.143 11 12 12 4.584 2.766 14 15 16 17 18 19 20 0.128 -2.179 -4.927 -7.262 -9.869 -12.069 -14.457 The most stable nucleus has a mass number 10
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