1. Predict the product of the following reaction: NaBH4 2-methyl-3-pentanone но он . A. он C. OH В. D.

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**Question:**  
1. Predict the product of the following reaction:

**Reaction:**  
- Reactant: 2-methyl-3-pentanone  
- Reagent: NaBH₄ (Sodium borohydride)  
- Product: ?

**Options:**  
- **A:** The compound has a hydroxyl group (OH) attached to the second carbon in a six-carbon chain with a methyl group attached to the third carbon.
- **B:** The compound has a hydroxyl group (OH) attached to the third carbon in a six-carbon chain with a methyl group on the second carbon.
- **C:** The compound has a hydroxyl group (OH) attached to the third carbon in a six-carbon chain with no other branches.
- **D:** The compound has a hydroxyl group (OH) attached to the fourth carbon in a six-carbon chain with no other branches.

**Explanation:**  
Sodium borohydride (NaBH₄) is a reducing agent commonly used to reduce ketones to secondary alcohols. In this reaction, 2-methyl-3-pentanone is expected to undergo reduction, forming an alcohol. The correct product will have the carbonyl group (C=O) of the ketone reduced to a hydroxyl group (OH), maintaining the carbon skeleton and substituents of the original reactant.
Transcribed Image Text:**Question:** 1. Predict the product of the following reaction: **Reaction:** - Reactant: 2-methyl-3-pentanone - Reagent: NaBH₄ (Sodium borohydride) - Product: ? **Options:** - **A:** The compound has a hydroxyl group (OH) attached to the second carbon in a six-carbon chain with a methyl group attached to the third carbon. - **B:** The compound has a hydroxyl group (OH) attached to the third carbon in a six-carbon chain with a methyl group on the second carbon. - **C:** The compound has a hydroxyl group (OH) attached to the third carbon in a six-carbon chain with no other branches. - **D:** The compound has a hydroxyl group (OH) attached to the fourth carbon in a six-carbon chain with no other branches. **Explanation:** Sodium borohydride (NaBH₄) is a reducing agent commonly used to reduce ketones to secondary alcohols. In this reaction, 2-methyl-3-pentanone is expected to undergo reduction, forming an alcohol. The correct product will have the carbonyl group (C=O) of the ketone reduced to a hydroxyl group (OH), maintaining the carbon skeleton and substituents of the original reactant.
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