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1. Point B is equidistant from points A and 4x Зх + 4 2. Find AB. 3. Find BC.

1. Point B is equidistant from points A and 4x Зх + 4 2. Find AB. 3. Find BC.

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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### Educational Text: 1. Point B is equidistant from points A and ______. 2. Find \( AB \). 3. Find \( BC \). #### Diagram Explanation: The diagram is a square inscribed within a diamond shape \( ABCD \). This central square is aligned such that each corner touches the midpoint of the adjacent sides of the diamond. The sides \( AB \), \( BC \), \( CD \), and \( DA \) of the diamond are labeled, where: - \( AB = 4x \) - \( BC = 3x + 4 \) Each side of the central square is perpendicular to the corresponding sides of the diamond, suggesting it plays a role in dividing the diamond into symmetrical sections. This symmetry and the equidistant property of point B to other points implies underlying geometric rules or theorems at work, likely relevant to solving the problems.
Transcribed Image Text:### Educational Text: 1. Point B is equidistant from points A and ______. 2. Find \( AB \). 3. Find \( BC \). #### Diagram Explanation: The diagram is a square inscribed within a diamond shape \( ABCD \). This central square is aligned such that each corner touches the midpoint of the adjacent sides of the diamond. The sides \( AB \), \( BC \), \( CD \), and \( DA \) of the diamond are labeled, where: - \( AB = 4x \) - \( BC = 3x + 4 \) Each side of the central square is perpendicular to the corresponding sides of the diamond, suggesting it plays a role in dividing the diamond into symmetrical sections. This symmetry and the equidistant property of point B to other points implies underlying geometric rules or theorems at work, likely relevant to solving the problems.
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