1. Plot the particle-size distribution hart. Particle Size Distribution Curve 100 90 80 70 * 60 50 30 20 10 10 Do 1 Do D10 0.1 0.01. Grain-size (mm) Figure 1:Particle-size Distribution Chart 2. Determine D10, D30, D60, Cu C- a. Di0-0.347 mm b. D30-0.651 mm c. D60-1.516 mm d. Cu-4.368 e. C-0.82 3. More than 50% passed through 4.75 mm Ca<6-or- Poorly Graded Sand 4. Fineness Modulus & Average Size a. FM=9.425 b. Avg Size =2.00 mm 5. | Conclusion Percent Finer (%)
1. Plot the particle-size distribution hart. Particle Size Distribution Curve 100 90 80 70 * 60 50 30 20 10 10 Do 1 Do D10 0.1 0.01. Grain-size (mm) Figure 1:Particle-size Distribution Chart 2. Determine D10, D30, D60, Cu C- a. Di0-0.347 mm b. D30-0.651 mm c. D60-1.516 mm d. Cu-4.368 e. C-0.82 3. More than 50% passed through 4.75 mm Ca<6-or- Poorly Graded Sand 4. Fineness Modulus & Average Size a. FM=9.425 b. Avg Size =2.00 mm 5. | Conclusion Percent Finer (%)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
100%
Please help me to explain the results of the Sieve Analysis for question #5 & explain how I might go about writing a conclusion.
Transcribed Image Text:1. Plot the particle-size distribution hart.
Particle Size Distribution Curve
100
90
80
70
60
50
40
30
20
10
10
0.1
0.01
Deo 1
D30
D10
Grain-size (mm)
Figure 1:Particle-size Distribution Chart
2. Determine D10, D30, D60, Cu, Ce
a. D10-0.347 mm
b. D30- 0.651 mm
c. D60 -1.516 mm
d. Cu-4.368
е. Се-0.82
3. More than 50% passed through 4.75 mm Cu< 6 -or- Poorly Graded Sand
4. Fineness Modulus & Average Size
a. FM =9.425
b. Avg Size =2.00 mm
5. |
Conclusion
Percent Finer (%)
Expert Solution
Introduction
Sieve analysis test is used to analyse the distribution of granular material by passing the material through a series of sieves where size of mesh decreases from top to bottom and the finest material collect on the pan.The amount of material retained on each sieve is use to determine the percent finess of material for all sizes of mesh of sieve
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