Pls, can you help me with this code without using an array?This is C language btw. Project 1:1. Player 1 will roll three dice and player 2 will roll two dice.2. The highest number rolled for each player are compared. If the attacker number is higher,the defender loses one army. If the attacker number is lower than or equal to the defendernumber, the attacker loses one army.3. The second highest number rolled for each player are compared. If the attacker number ishigher, the defender loses one army. If the attacker number is lower than or equal to thedefender number, the attacker loses one army.The third die rolled by the attacker is not used. There are three possible outcomes: Theattacker loses two armies, the defender loses two armies, or each person loses one army4. Your code must print out:a. The three numbers rolled by the attacker, in decreasing order (use tabs)b. The two numbers rolled by the defender, in decreasing order (use tabs)c. The outcome of the attack.For example, The attacker roles a 3, 6, 6. The defender roles a 4,6Sample output for Project 1 would be:Attacker:3Defender6.4Both players lose one army.

Answered: 1. Player 1 will roll three dice and…

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Author:James Kurose, Keith Ross

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Pls, can you help me with this code without using an array?

This is C language btw.

Project 1:
1. Player 1 will roll three dice and player 2 will roll two dice.
2. The highest number rolled for each player are compared. If the attacker number is higher,
the defender loses one army. If the attacker number is lower than or equal to the defender
number, the attacker loses one army.
3. The second highest number rolled for each player are compared. If the attacker number is
higher, the defender loses one army. If the attacker number is lower than or equal to the
defender number, the attacker loses one army.
The third die rolled by the attacker is not used. There are three possible outcomes: The
attacker loses two armies, the defender loses two armies, or each person loses one army
4. Your code must print out:
a. The three numbers rolled by the attacker, in decreasing order (use tabs)
b. The two numbers rolled by the defender, in decreasing order (use tabs)
c. The outcome of the attack.
For example, The attacker roles a 3, 6, 6. The defender roles a 4,6
Sample output for Project 1 would be:
Attacker:
3
Defender
6.
4
Both players lose one army.

Expert Solution

Step 1

Program Code:

#include<stdio.h>
main()
{
int a1,a2,a3,d1,d2,highest_a,shighest_a;
int highest_d,shighest_d,flag_a,flag_d;
printf("The attacker roles:");
scanf("%d%d%d",&a1,&a2,&a3);
printf("\nThe defender roles:");
scanf("%d%d",&d1,&d2);
if(a1>a2 && a1>a3)
{
highest_a=a1;
if(a2>a3)
{
shighest_a=a2;
}
else{
shighest_a=a3;
}
}
else if(a2>a1 && a2>a3)
{
highest_a=a2;
if(a1>a3)
{
shighest_a=a1;
}
else{
shighest_a=a3;
}
}
else
{
highest_a=a3;
if(a1>a2)
{
shighest_a=a1;
}
else{
shighest_a=a2;
}
}
if(d1>d2)
{
highest_d=d1;
shighest_d=d2;
}
else{
highest_d=d2;
shighest_d=d1;
}
printf("\nAttacker: %d %d",highest_a,shighest_a);
printf("\nDefender: %d %d",highest_d,shighest_d);
if(highest_a>highest_d)
{
flag_a=1;
}
else{
flag_a=0;
}
if(shighest_a>shighest_d)
{
flag_d=1;
}
else{
flag_d=0;
}
if(flag_a==1 && flag_d==1)
{
printf("\nDefender loses two army");
}
else if(flag_a==0 && flag_d==0)
{
printf("\nAttacker loses two army");
}
else{
printf("\nBoth players lose one army");
}
return 0;
}